这几天我遇到了一个问题。在我的MS SQL数据库中,我有一个文章表(它们的详细信息,如插入日期,插入用户和其他人员)和一个表格,其中包含多种语言的文章正文。我希望文章正文是用户首选语言。但并非所有文章都使用所有语言。所以,很高兴,首先用用户首选的语言搜索文章,如果不存在的话,用第一语言来获取正文。
为此,我使用了一个函数。 WHERE子句是这样的:
WHERE [tblBody].[Language] = @Language AND
[tblTitle].[Language] = @Language
但如果它会是这样的话会很好: 选择(如果身体是我的首选语言得到那个身体;否则给我一个(也许我理解))
我希望你明白我想做什么,女巫是我的问题。
提前谢谢!
更新
这是我需要修改的实际查询:
ALTER FUNCTION [fx_GetNews]
(
@MinimumPermission INT,
@UserID UNIQUEIDENTIFIER,
@OwnerID UNIQUEIDENTIFIER = NULL,
@Title NVARCHAR(250) = NULL,
@Body VARCHAR(150) = NULL,
@InsertDateStart DATETIME = NULL,
@InsertDateEnd DATETIME = NULL,
@CreatedByUserID UNIQUEIDENTIFIER = NULL,
@ExpirationDate DATETIME = NULL,
@Language VARCHAR(150)
)
RETURNS @News TABLE
(
[Id] UNIQUEIDENTIFIER
,[OwnerID] UNIQUEIDENTIFIER
,[Title] NVARCHAR(250)
,[TitlePictureUrl] VARCHAR(150)
,[Body] NVARCHAR(max)
,[Visible] BIT
,[InsertDate] DATETIME
,[CreatedByUserId] UNIQUEIDENTIFIER
,[ModifiedDate] DATETIME
,[ModifiedByUserId] UNIQUEIDENTIFIER
,[ModifiedByPerson] VARCHAR(250)
,[ExpirationDate] DATETIME
,[CreatedByPerson] VARCHAR(250)
,[Permission] INT
)
AS
BEGIN
INSERT INTO @News
([Id]
,[OwnerID]
,[Title]
,[TitlePictureUrl]
,[Body]
,[Visible]
,[InsertDate]
,[CreatedByUserId]
,[ModifiedDate]
,[ModifiedByUserId]
,[CreatedByPerson]
,[ModifiedByPerson]
,[ExpirationDate]
,[Permission])
SELECT
[dbo].[tblNews].[Id]
,[dbo].[tblNews].[OwnerID]
,CAST([tblTitle].[Text] AS VARCHAR(150))
,[dbo].[tblNews].[TitlePictureUrl]
,[tblBody].[Text]
,[dbo].[tblNews].[Visible]
,[dbo].[tblNews].[InsertDate]
,[dbo].[tblNews].[CreatedByUserId]
,[dbo].[tblNews].[ModifiedDate]
,[dbo].[tblNews].[ModifiedByUserId]
,[dbo].[tblNews].[CreatedByPerson]
,[dbo].[tblNews].[ModifiedByPerson]
,[dbo].[tblNews].[ExpirationDate]
,[eportofolii].[fx_GetPermissionForObject] (@UserID, [dbo].[tblNews].[ID], 1, 1)
FROM [dbo].[tblNews]
INNER JOIN [dbo].[tblAdmTranslateText] AS [tblBody] ON
[tblBody].[OwnerID] = [dbo].[tblNews].[ID]
INNER JOIN [dbo].[tblAdmTranslateText] AS [tblTitle] ON
[tblTitle].[OwnerID] = [dbo].[tblNews].[ID]
WHERE
[eportofolii].[fx_GetPermissionForObject] (@UserID, [dbo].[tblNews].[ID], 1, 1) >= @MinimumPermission AND
([dbo].[tblNews].[OwnerID] = ISNULL(@OwnerID, [dbo].[tblNews].[OwnerID]) OR [dbo].[tblNews].[OwnerID] IS NULL) AND
[tblTitle].[Text] LIKE '%' + ISNULL(@Title, '') + '%' AND
[tblBody].[Text] LIKE '%' + ISNULL(@Body, '') + '%' AND
([dbo].[tblNews].[InsertDate] BETWEEN ISNULL(@InsertDateStart, ([dbo].[tblNews].[InsertDate] - 7)) AND ISNULL(@InsertDateEnd, [dbo].[tblNews].[InsertDate] + 1)) AND
[dbo].[tblNews].[CreatedByUserID] = ISNULL(@CreatedByUserID, [dbo].[tblNews].[CreatedByUserID]) AND
([dbo].[tblNews].[ExpirationDate] > ISNULL(@ExpirationDate, GETDATE() - 1) OR [dbo].[tblNews].[ExpirationDate] IS NULL) AND
[tblBody].[UDF_2] = 'Body' AND
[tblTitle].[UDF_2] = 'Title' AND
[tblBody].[UDF_1] = 'News' AND
[tblTitle].[UDF_1] = 'News' AND
[tblBody].[Language] = @Language AND
[tblTitle].[Language] = @Language
ORDER BY [InsertDate] DESC
RETURN
END
问题出在最后:
[tblBody].[Language] = @Language AND
[tblTitle].[Language] = @Language
谢谢!
答案 0 :(得分:2)
;WITH x AS
(
SELECT b.[Language], /* other columns from b */
rn = ROW_NUMBER() OVER (PARTITION BY b.article_id_of_some_kind
ORDER BY CASE WHEN t.[Language] = @Language THEN 1 ELSE 2 END)
FROM dbo.tblBody AS b
INNER JOIN dbo.tblLanguage AS l
ON b.LanguageID = l.LanguageID -- guessing here
)
SELECT /* cols */ FROM x WHERE rn = 1;
如果首选语言不可用,将返回任意语言。您可以通过修改内部ORDER BY
来进一步完善它。
答案 1 :(得分:0)
你想做的事情有点复杂。您希望以所需语言(如果存在)返回文章,如果不存在,则返回其他语言。
为此,窗口函数非常有用:
select t.*
from (select blah,
max(case when [tblBody].[Language] = @Language then 1 else 0 end) over (partition by article) as HasLanguage
from whatever
where [tblTitle].[Language] = @Language
) t
where HasLanguage = 1 or [tblBody].[Language] <> @Language
答案 2 :(得分:0)
select B.*
from bodies as B
where exists (
select 1 from (
select b.article, coalesce( u.language, b.language ) as language
from bodies as b
left join users as u
on b.language = u.language
and u.user = @user
where b.article = @article
and b.default_language = 'TRUE' -- or whatever
) as A
on A.article = B.Article
and A.language = B.language
)
您必须在两种语言之间进行选择:用户的语言和文章的语言。你可以使用UNION
或coalesce
(因为外连接是一种联合),而后者更简单。
答案 3 :(得分:-1)