根据Facebook Javascript SDK documentation,
可以通过设置status:true来检查用户的状态 当你打电话给FB.init。
要接收此通话的回复,您必须订阅 auth.statusChange事件。
我相信我这样做是正确的,但我的示例中的'状态更改'日志永远不会触发:
window.fbAsyncInit = function() {
FB.init({
appId : 'xxxxxxxxxxxx', // App ID
channelUrl : '../channel.html', // Channel File
status : true, // check login status
cookie : true, // enable cookies to allow the server to access the session
xfbml : true // parse XFBML
});
FB.Event.subscribe('auth.statusChange', function(response) {
console.log("status change!");
});
...
});
此文档是否不正确?或者我做错了什么?
答案 0 :(得分:0)
我认为最后而不是});是};
也可能是你没有开始。这对我有用:
$(document).ready(function() {
var app_id = 'xxxxxxxxxxxxxx';
var start = function (){
window.fbAsyncInit = function() {
FB.init({
appId : app_id,
status : true,
cookie : true,
xfbml : true,
version : 'v2.7'
});
FB.Event.subscribe('auth.statusChange', function(response) {
var status = response.status;
console.log(response.status);
if (status === "connected") {
//
}
});
};
}
start();
});
答案 1 :(得分:0)
您可以尝试这种方式。
<script type="application/javascript">
function statusChangeCallback(response) { // Called with the results from FB.getLoginStatus().
console.log('statusChangeCallback');
console.log(response); // The current login status of the person.
if (response.status === 'connected') { // Logged into your webpage and Facebook.
console.log("User connected, name: " + response.name);
} else { // Not logged into your webpage or we are unable to tell.
console.log("user not conneted");
}
}
window.fbAsyncInit = function () {
FB.init({
appId: '{your-app-id}',
cookie: true,
xfbml: true,
version: '{api-version}'
});
FB.getLoginStatus(function (response) { // Called after the JS SDK has been initialized.
statusChangeCallback(response); // Returns the login status.
});
};
(function (d, s, id) {
var js, fjs = d.getElementsByTagName(s)[0];
if (d.getElementById(id)) {
return;
}
js = d.createElement(s);
js.id = id;
js.src = "https://connect.facebook.net/en_US/sdk.js";
fjs.parentNode.insertBefore(js, fjs);
}(document, 'script', 'facebook-jssdk'));
</script>