我的应用程序使用EF-CodeFirst 5(dll ver 4.4.0.0,on .net 4.0)。
我需要能够读取实体元数据,以便我可以为给定的条目类型获取以下信息:
我可以通过在属性列表上编写foreach循环来获取此信息,然后通过依赖所有虚拟引用来“识别”它们,但我觉得这不是“正确”的方式。我知道EdmxWriter
可以以xml格式提供该信息,但它通过访问不可公开访问的InternalContext来实现,我想直接获得强类型列表/数组,而不使用该xml。我应该使用哪种API(如果有这样的API,似乎我找不到它)?
答案 0 :(得分:26)
using (var db = new MyDbContext())
{
var objectContext = ((IObjectContextAdapter)db).ObjectContext;
var container = objectContext.MetadataWorkspace.GetEntityContainer(objectContext.DefaultContainerName, DataSpace.CSpace);
foreach (var set in container.BaseEntitySets)
{
// set.ElementType.
foreach (var metaproperty in set.MetadataProperties)
{
// metaproperty.
}
}
// ...or...
var keyName = objectContext
.MetadataWorkspace
.GetEntityContainer(objectContext.DefaultContainerName, DataSpace.CSpace)
.BaseEntitySets
.First(meta => meta.ElementType.Name == "Question")
.ElementType
.KeyMembers
.Select(k => k.Name)
.FirstOrDefault();
}
更具体地......
foreach (var set in container.BaseEntitySets)
{
var dependents = ((EntitySet)(set)).ForeignKeyDependents;
var principals = ((EntitySet)(set)).ForeignKeyPrincipals;
var navigationProperties = ((EntityType)(set.ElementType)).NavigationProperties;
foreach (var nav in navigationProperties)
{
// nav.RelationshipType;
}
}
其中一些属性似乎没有暴露给“一般公众”,所以你需要使用反射 - 或者找一些更聪明的方法 - 但是那里有很多信息。
这些链接还有更多信息......
How to get first EntityKey Name for an Entity in EF4
How can I extract the database table and column name for a property on an EF4 entity?
修改强>: 使用您的navigationProperties列表作为起点,我得到了我需要的一切:
ManyToManyReferences = navigationProperties.Where(np =>
np.FromEndMember.RelationshipMultiplicity == RelationshipMultiplicity.Many &&
np.ToEndMember.RelationshipMultiplicity == RelationshipMultiplicity.Many)
.Select(np => Extensions.CreateLambdaExpression<TEntity>(np.Name))
.ToList();
OneToManyReferences = navigationProperties.Where(np =>
(np.FromEndMember.RelationshipMultiplicity == RelationshipMultiplicity.One ||
np.FromEndMember.RelationshipMultiplicity == RelationshipMultiplicity.ZeroOrOne) &&
np.ToEndMember.RelationshipMultiplicity == RelationshipMultiplicity.Many)
.Select(np => Extensions.CreateLambdaExpression<TEntity>(np.Name))
.ToList();
ManyToOneReferences = navigationProperties.Where(np =>
np.FromEndMember.RelationshipMultiplicity == RelationshipMultiplicity.Many &&
(np.ToEndMember.RelationshipMultiplicity == RelationshipMultiplicity.One ||
np.ToEndMember.RelationshipMultiplicity == RelationshipMultiplicity.ZeroOrOne))
.Select(np => Extensions.CreateLambdaExpression<TEntity>(np.Name))
.ToList();
OneToOneReferences = navigationProperties.Where(np =>
np.FromEndMember.RelationshipMultiplicity == RelationshipMultiplicity.One &&
np.ToEndMember.RelationshipMultiplicity == RelationshipMultiplicity.One)
.Select(np => Extensions.CreateLambdaExpression<TEntity>(np.Name))
.ToList();
CreateLambdaExpression方法不是我的礼貌,积分转到Jon Skeet,代码是在this answer
的帮助下创建的这是我的CreateLambdaExpression方法:
public static Expression<Func<TEntity, object>> CreateLambdaExpression<TEntity>(string propertyName)
{
ParameterExpression parameter = Expression.Parameter(typeof (TEntity), typeof (TEntity).Name);
Expression property = Expression.Property(parameter, propertyName);
return Expression.Lambda<Func<TEntity, object>>(property, new[] {parameter});
}