Question

我正在尝试使用Python从一个非常复杂的JSON文件中获取一些信息。以下是文件中的一个对象：

{
"__metadata": {
"uri": "/Students/news/_vti_bin/ListData.svc/Posts(4)", "etag": "W/\"2\"", "type": "Microsoft.SharePoint.DataService.PostsItem"
}, "Title": "Term 2 Round 2 draws", "Body": "<div class=\"ExternalClass0BC1BCA4D3EE45A4A1F34086034FE827\"><p>\u200bAs there is no Gonzagan this week the following Senior Sport information has been provided here.\r\n\t    </p>\r\n<ul><li><a target=\"_blank\" href=\"/Intranet/students/news_resources/2011/Term2/Knox _wet_weather.pdf\">Knox _wet_weather</a> Cancellations, please see <a target=\"_blank\" href=\"http://www.twitter.com/SACWetWeather\">twitter page</a> for further news.</li>\r\n<li><a target=\"_blank\" href=\"/Intranet/students/news_resources/2011/Term2/2011_Football_round_2.pdf\">2011 Football draw Round 2</a></li>\r\n<li><a target=\"_blank\" href=\"/Intranet/students/news_resources/2011/Term2/2011_Rugby_round_2.pdf\">2011 Rugby draw Round 2</a></li></ul>\r\n<p></p></div>", "Category": {
"__deferred": {
"uri": "/Students/news/_vti_bin/ListData.svc/Posts(4)/Category"
}
}, "Published": "\/Date(1308342960000)\/", "ContentTypeID": "0x0110001F9F7104FDD3054AAB40D8561196E09E", "ApproverComments": null, "Comments": {
"__deferred": {
"uri": "/_vti_bin/ListData.svc/Posts(4)/Comments"
}
}, "CommentsId": 0, "ApprovalStatus": "0", "Id": 4, "ContentType": "Post", "Modified": "\/Date(1309122092000)\/", "Created": "\/Date(1309120597000)\/", "CreatedBy": {
"__deferred": {
"uri": "/Students/news/_vti_bin/ListData.svc/Posts(4)/CreatedBy"
}
}, "CreatedById": 1, "ModifiedBy": {
"__deferred": {
"uri": "/Students/news/_vti_bin/ListData.svc/Posts(4)/ModifiedBy"
}
}, "ModifiedById": 1, "Owshiddenversion": 2, "Version": "1.0", "Path": "/Students/news/Lists/Posts"
},

我无法围绕编辑这个。将它转换为python字典似乎混淆了属性的顺序，使我无法找到一个对象开始而另一个开始的位置。我最好的方法是提取“标题”，“正文”和“已发布”的键和值，以及如何为多个对象执行此操作？

Answer 1

import json

obj = json.loads(json_input)

for record in obj:
    print obj["title"]
    print obj["body"]
    print obj["published"]

假设json_input是上面的代码片段，以字符串形式，或者已经通过文件读入。另请注意，我假设上面的代码段是基于您的问题的集合。

<强>更新

根据该示例，您有另一个最初发布的代码段中没有的图层。

将循环更改为：

for record in obj["d"]["results"]:
    ...

Answer 2

我假设您的主JSON对象是这些对象的数组。以下是我打印出您所追求的信息的方式：

import json

main_array = json.load('my_json_file.json')

for sub_object in main_array:
    print "Title: {}\nBody: {}\nPublished: {}\n".format(
        sub_object['Title'], sub_object['Body'], sub_object['Published']
    )

从Python中的非常复杂的JSON文件中提取

2 个答案: