Question

我有一个使用下面的代码创建的下拉菜单，该菜单从品牌表中提取所有品牌。它使用while循环，从而按字母顺序显示菜单上的所有内容（即Adiddas等）。因此，我不会逐行将它们列为单独的<options>。

echo "<form action=\"type.INC.php\" method=\"get\">\n";
echo "<select name=\"brand\">\n";

$stmt = mysqli_stmt_init($hook);
if($stmt=mysqli_prepare($hook,"SELECT brandid, brandname FROM brands WHERE brandid "));
{
mysqli_stmt_bind_param($stmt,"i", $brandid);
mysqli_stmt_execute($stmt);
mysqli_stmt_bind_result($stmt, $brandid, $brandname);
while(mysqli_stmt_fetch($stmt))
    {
    $brandname = htmlspecialchars($brandname, ENT_QUOTES, 'UTF-8');
    echo "<option value=\"$brandid\">$brandname </option>"; 
    }    
echo "</select>\n";
echo "<input name=\"submit\" type=\"submit\" id=\"brandid\" value=\"submit\" />\n";
echo "</form> \n";

如何将“SELECT A BRAND”这个句子显示为默认的第一个值？我应该只在品牌表中输入“SELECT A BRAND”并为其指定一个零的主要ID吗？

有更好的方法吗？

我对此问题的所有搜索都会产生与'select = selected属性'相关的主题。

谢谢，仁

Answer 1

只需在循环之前手动添加：

echo "<form action=\"type.INC.php\" method=\"get\">\n";
echo "<select name=\"brand\">\n";
// Select a brand, empty value:
echo "<option value=\"\">(SELECT A BRAND)</option>";

$stmt = mysqli_stmt_init($hook);
if($stmt=mysqli_prepare($hook,"SELECT brandid, brandname FROM brands WHERE brandid "));
{
    mysqli_stmt_bind_param($stmt,"i", $brandid);
    mysqli_stmt_execute($stmt);
    mysqli_stmt_bind_result($stmt, $brandid, $brandname);
    while(mysqli_stmt_fetch($stmt))
    {
        $brandname = htmlspecialchars($brandname, ENT_QUOTES, 'UTF-8');
        echo "<option value=\"$brandid\">$brandname </option>"; 
    }    
    echo "</select>\n";
    echo "<input name=\"submit\" type=\"submit\" id=\"brandid\" value=\"submit\" />\n";
    echo "</form> \n";

Answer 2

添加

echo "<option>SELECT A BRAND</option>";

作为代码的第三行。

在下拉菜单中显示“选择...”

2 个答案: