Question

with open('rules_test1Fold0w4_sample00ll1.dat') as fileobj:
    lines = list(fileobj)
actualrules=''
for index in sortrule:
    print lines[index]

我有这段代码打印出.dat文件的某些行，但我想要做的是让每一行成为数组中的元素。例如，如果我的文件在

中有这个

`'Once upon a time there was a young
  chap of the name of Peter he had a
  great friend called Claus'`

数组将为[Once upon a time there was a young,chap of the name of Peter he had a,great friend called Claus]

Answer 1

您发布的代码会将输入文件的行放入list。

>>> with open('/etc/passwd') as fileobj:
...   lines = list(fileobj)
... 
>>> type(lines)
<type 'list'>
>>> lines[0]
'root:x:0:0:root:/root:/bin/bash\n'
>>>

此外，您发布的代码会对其应用选择过滤器，打印出sortrule中指定的行。如果您希望将那些行存储在list中，请尝试列表理解：

selected_lines = [lines[index] for index in sortrule]

Answer 2

你可以这样做。

with open('rules_test1Fold0w4_sample00ll1.dat') as fileobj:
    lines = fileobj.readlines()
actualrules=''
for index in sortrule:
    print lines[index]

这会给你一个由\ n

分隔的行列表

Answer 3

在您的情况下，您只需要一维数组，因此列表足够了。并且您的代码已经将每一行存储到列表变量行中。

从文件中获取数据并将其放入数组中

3 个答案: