Android android.view.WindowManager $ BadTokenException

Question

我正在调用一个调用对话框的方法。

showDialog(SOME_MESSAGE);

 switch (id) {
    case SOME_MESSAGE:
        pDialog = ProgressDialog.show(LocalActivity.this, "",
                getResources().getString(R.string.synchronizingData), true);
        pDialog.setOnKeyListener(keyListener);          
        return pDialog;

我没有在onstop中关闭此进度对话框 我得到android.view.WindowManager$BadTokenException

android.view.WindowManager$BadTokenException: Unable to add window -- token android.app.LocalActivityManager$LocalActivityRecord@44f1dfd8 is not valid; is your activity running?

当我执行另一项活动并快速按回2次

时会发生这种情况