Question

我有一个脚本插入两个单独的数据库表：成分和方向。首先，我使用$this->db->query($sql)，第二个：$this->db->query($sql2)（我正在使用CodeIgniter）。这是我的代码：

foreach($_POST as $key => $value) {
        $value = $this->input->post($key);
        $directions = $this->input->post('directions');
        $ingredientQTY = $this->input->post('ingredientQTY');
        $measurements = $this->input->post('measurements');
        $ingredientNAME = $this->input->post('ingredientNAME');
        $ingredientsROW[] = array($ingredientQTY, $measurements, $ingredientNAME);

        //For inserting ingredients
        for ($i = 0, $count = count($ingredientQTY); $i < $count; $i++) {
            $rows[] = array(
                'ingredientamount'      => $ingredientQTY[$i],
                'ingredientType'        => $measurements[$i],
                'ingredientname'        => $ingredientNAME[$i],
                'recipe_id'             => $recipe_id,
                'order'                 => $i + 1,
                'user_id'               => $user_id
            );
            $sql = "INSERT `ingredients` (`ingredientamount`,`ingredientType`,`ingredientname`,`recipe_id`, `listOrder`, `user_id`) VALUES ";
            $coma = '';
            foreach ($rows as $oneRow) {
                $sql .= $coma."('".implode("','",$oneRow)."')";
                $coma = ', ';
            }

        }
        $this->db->query($sql);//Insert Query for ingredients

        //For inserting directions
        for ($i = 0, $count = count($directions); $i < $count; $i++) {
            $rows[] = array(
                'direction'     => $directions[$i],
                'recipe_id'             => $recipe_id,
                'order'                 => $i + 1,
                'user_id'               => $user_id
            );
            $sql2 = "INSERT `directions` (`direction`,`recipe_id`,`listOrder`,`user_id`) VALUES ";
            $coma = '';
            foreach ($rows as $oneRow) {
                $sql2 .= $coma."('".implode("','",$oneRow)."')";
                $coma = ', ';
            }
        }
        $this->db->query($sql2);    //Insert Query for directions
        break;
    }

我应该有两个单独的sql语句，但由于某种原因它们被合并，并生成以下错误：

Column count doesn't match value count at row 1

INSERT `directions` (`direction`,`recipe_id`,`listOrder`,`user_id`) VALUES ('1','Bunch','Cilantro','1','1','1'), ('3','Cup','Sugar','1','2','1'), ('First, combine the cilantro and sugar','1','1','1'), ('then eat. ','1','2','1')

也应该有一个INSERT ingredients，但它的值会合并到INSERT directions语句中。

为什么要合并两个SQL语句？

Answer 1

代码的前半部分构建$rows以插入所有成分，然后下半部分构建$rows以插入所有方向，但它永远不会清除$rows。当你去做方向时，成分仍在阵列中。

此外，我认为您经常调用SQL。您的for $i循环和foreach $rows循环不应该嵌套;他们应该是一个跟随另一个。尝试这样的事情：

for ($i = 0, $count = count($ingredientQTY); $i < $count; $i++) {
  $rows[] = array(
    'ingredientamount' => $ingredientQTY[$i],
    'ingredientType'   => $measurements[$i],
    'ingredientname'   => $ingredientNAME[$i],
    'recipe_id'        => $recipe_id,
    'order'            => $i + 1,
    'user_id'          => $user_id
  );
} // <-- FIRST FOR LOOP SHOULD END HERE

$sql = "INSERT `ingredients` (`ingredientamount`,`ingredientType`,`ingredientname`,`recipe_id`, `listOrder`, `user_id`) VALUES ";
$coma = '';
foreach ($rows as $oneRow) {
  $sql .= $coma."('".implode("','",$oneRow)."')";
  $coma = ', ';
}
//  } <-- FIRST FOR LOOP USED TO END HERE; PROBABLY NOT RIGHT

$this->db->query($sql);//Insert Query for ingredients

$rows = array(); // <-- Clear out $rows to reuse it for directions

清除$rows阵列后，您可以转到指示。与成分一样，将循环放在一个接一个而不是嵌套。

数据库插入是否合并？

1 个答案: