我正在试图弄清楚如何使用属性修饰特定的Mongoid记录,以便to_json
返回包含该属性(请不要告诉我将特定参数传递给to_json
- 这是双重嵌套,在这里不起作用)。有没有办法做到这一点?我能想出的就是
my_record[:my_special_attribute]='foo'
当然不起作用。
答案 0 :(得分:1)
以下两个版本可能适合您:
覆盖to_json
:
require 'mongoid'
Mongoid.load!("mongoid.yml", :development)
class MyClass
include Mongoid::Document
def to_json(options = {})
json = JSON.parse(super)
json['my_special_attribute'] = 'whatever you want'
json.to_json
end
end
p MyClass.new.to_json # => "{\"_id\":\"5155899ee44f7ba6e7000001\",\"my_special_attribute\":\"whatever you want\"}"
将参数传递给to_json
(抱歉 - 为了完整起见):
require 'mongoid'
Mongoid.load!("mongoid.yml", :development)
class MyClass
include Mongoid::Document
def not_a_field
"whatever you want"
end
end
p MyClass.new.to_json(methods: :not_a_field) # => "{\"_id\":\"51558b67e44f7bddb7000001\",\"my_special_attribute\":\"whatever you want\"}"
您甚至可以将此选项传递给嵌套记录(我猜这是双重嵌套的意思):
my_record.to_json(include: {other_class: {methods: :special_field}})
您还可以将此方法添加到一个特定记录(=实例):
my_object = MyClass.new
def my_object.not_a_field
"whatever you want"
end
p my_object.to_json(methods: :not_a_field) # => "{\"_id\":\"51558cc8e44f7bd1f6000001\",\"not_a_field\":\"whatever you want\"}"