Question

我试图让while循环显示从表中选择的所有记录，并迭代封装在＆lt;中的结果。 div＆gt;。我的查询正在运行，而while正在显示某些内容......但只显示最新记录。我无法弄清楚为什么会这样，而且我对PHP很新，所以任何帮助都会很棒。

代码：

<?php
//Connect to database and select table
$conn = mysql_connect("", "", "") or die(mysql_error());
mysql_select_db("substest", $conn) or die(mysql_error());
//Issue query
$get_features = "SELECT ID, Title, DateReceived, Synopsis FROM features ORDER BY ID";
$r_get_features = mysql_query($get_features) or die(mysql_error);

if(mysql_num_rows($r_get_features) < 1)  {
    $display_block = "<div class=\"inner\"><h2>Nothing to display</h2></div>";
}
else {
    while($feat_array = mysql_fetch_array($r_get_features)) {
    $feat_id = $feat_array["ID"];
    $feat_title = stripslashes($feat_array["Title"]);
    $feat_dater = stripslashes($feat_array["DateReceived"]);
    $feat_synopsis = stripslashes($feat_array["Synopsis"]);

    $display_block = "<div class=\"inner\">";
    $display_block .= "<h2>".$feat_title."</h2>";
    $display_block .= "<label for \"id\">ID:</label>";
    $display_block .= "<span class=\"formresult\" id=\"id\">".$feat_id."</span><br />";
    $display_block .= "<label for=\"title\">Title:</label>";
    $display_block .= "<span class=\"formresult\" id=\"title\">".$feat_title."</span><br />";
    $display_block .= "<label for=\"datereceived\">Date Received:</label>";
    $display_block .= "<span class=\"formresult\" id=\"datereceived\">".$feat_dater."</span><br />";
    $display_block .= "<label for=\"synopsis\">Synopsis:</label>";
    $display_block .= "<span class=\"formresult\" id=\"synopsis\">".$feat_synopsis."</span><br />";
    $display_block .= "</div>";
}
}
?>
<html>
<head>
<title>Galway Film Fleadh - View Submitted Feature Films</title>
<link href="css/submissions.css" rel="stylesheet" type="text/css" />
</head>

<body>
<div id="wrapper">
    <div class="inner">
        <h1>Galway Film Fleadh - View Submitted Films</h1>
    </div>
    <?php
        print $display_block;
    ?>
</div>        
</body>
</html>

Answer 1

你为每个循环迭代覆盖$display_block：

$display_block = "<div class=\"inner\">";

在循环之前定义，然后将上面的行更改为：

$display_block .= "<div class=\"inner\">";

Answer 2

替换此行

$display_block = "<div class=\"inner\">";

通过

$display_block .= "<div class=\"inner\">";

Answer 3

自

 $display_block = "<div class=\"inner\">";

在循环内所以在while循环中的每次迭代之后，div都会被实现....

你需要保留旧值，所以你必须连接它... 用

替换它

 $display_block .= "<div class=\"inner\">";

Answer 4

$display_block = "<div class=\"inner\">";

在while循环中，所以每次迭代它都会获得一个新值并且不会保留前一个。

Answer 5

尝试将您的时间更改为：

while($feat_array = mysql_fetch_array($r_get_features, MYSQLI_ASSOC)) {
...

PHP / MySQL - while循环只显示最新输入的记录

5 个答案: