Question

我正在使用Powershell和7zip提取.tgz档案。 7zip具有强制详细模式并污染我的屏幕。我只想显示错误消息。我已经使用FIND删除了标准消息：

代码：

  Write-Host "Extracting "$strArgument

  # extract tgz to tar
  & "$7z" x "-y" $strArgument | FIND /V "ing  " | FIND /V "Igor Pavlov" | FIND /V "Processing " | FIND /V "Everything is Ok" | FIND /V "Folders: " | FIND /V "Files: " | FIND /V "Size: " | FIND /V "Compressed: " | FIND /V "Processing archive: "

  # path to .tar
  $strArgument = $strArgument.Replace(".tgz", ".tar")
  $strArgument = $strArgument.Replace("i\data\", "")

  # extract tar to file
  #Write-Host $strArgument
  & "$7z" x "-y" $strArgument | FIND /V "ing  " | FIND /V "Igor Pavlov" | FIND /V "Processing " | FIND /V "Everything is Ok" | FIND /V "Folders: " | FIND /V "Files: " | FIND /V "Size: " | FIND /V "Compressed: " | FIND /V "Processing archive: "

这给了我一个包含大量空行的输出：

Extracting  Q:\mles\etl-i_test\i\data\divider-bin.tgz










Extracting  Q:\mles\etl-i_test\i\data\divider-conf.tgz
...

但我只是想：

Extracting  Q:\mles\etl-i_test\i\data\divider-bin.tgz
Extracting  Q:\mles\etl-i_test\i\data\divider-conf.tgz

如何从流中删除空白行？是否有强大的FIND开关？

Answer 1

我知道最简单的方法是通过-match运行结果并过滤掉任何不包含非空格的内容：

Write-Host "Extracting "$strArgument

  # extract tgz to tar
  & "$7z" x "-y" $strArgument | FIND /V "ing  " | FIND /V "Igor Pavlov" | FIND /V "Processing " | FIND /V "Everything is Ok" | FIND /V "Folders: " | FIND /V "Files: " | FIND /V "Size: " | FIND /V "Compressed: " | FIND /V "Processing archive: "

  # path to .tar
  $strArgument = $strArgument.Replace(".tgz", ".tar")
  $strArgument = $strArgument.Replace("i\data\", "")

  # extract tar to file
  #Write-Host $strArgument
  (& "$7z" x "-y" $strArgument | FIND /V "ing  " | FIND /V "Igor Pavlov" | FIND /V "Processing " |   ND /V "Everything is Ok" | FIND /V "Folders: " | FIND /V "Files: " | FIND /V "Size: " | FIND /V "Compressed: " | FIND /V "Processing archive: ") -match '\S'

Answer 2

find没有这样的开关，但您可以将findstr替换为正则表达式：

... | findstr /r /v "^$"

从Powershell中的7zip输出流中删除空行

2 个答案: