我正在做一些关于C ++的自学,并且正在做一些关于数组,循环等的章节。有很多练习,而我所引用的练习非常简单。初始化两行和三列的两个矩阵。
输出矩阵的内容(按指定格式),然后执行第三个矩阵中的加法。输出完成后输出第三个数组。我的代码有效,但我认为有更好的方法来输出而不是解决每个matrice元素?我正在考虑另一个循环,因为这是练习前的章节,或者这是否可以接受?
#include <iostream>
#include <string>
using namespace std;
int main()
{
int amatrix[2][3]=
{
{-5, 2, 8},
{1, 0, 0},
};
int bmatrix[2][3]=
{
{1, 0, 2},
{0, 3, -6},
};
int cmatrix[2][3]=
{
{0, 0, 0},
{0, 0, 0},
};
//add generated matrices
for (int i = 0; i <= 1; i++)
{
for (int j =0; j <= 2; j++)
{
cmatrix[i][j]=amatrix[i][j]+bmatrix[i][j];
}
}
//output to screen - NEED ADVICE FROM HERE
cout << "A= " << endl;
cout << amatrix[0][0] << ", " << amatrix[0][1] << ", " << amatrix[0][2] << endl;
cout << amatrix[1][0] << ", " << amatrix[1][1] << ", " << amatrix[1][2] << endl << endl;
cout << "B= " << endl;
cout << bmatrix[0][0] << ", " << bmatrix[0][1] << ", " << bmatrix[0][2] << endl;
cout << bmatrix[1][0] << ", " << bmatrix[1][1] << ", " << bmatrix[1][2] << endl << endl;
cout << "C= " << endl;
cout << cmatrix[0][0] << ", " << cmatrix[0][1] << ", " << cmatrix[0][2] << endl;
cout << cmatrix[1][0] << ", " << cmatrix[1][1] << ", " << cmatrix[1][2] << endl << endl;
}
答案 0 :(得分:2)
cout << amatrix[i][j]
答案 1 :(得分:0)
使用for
之类的循环,类似下面的代码来打印cmatrix
:
#include <iostream>
// ...
for (int i=0; i < 2; i++)
{
for (int j=0; j < 3; j++)
{
std::cout << cmatrix[i][j] << "\t";
}
std::cout << std::endl;
}