我在查询时遇到了麻烦。
SELECT * FROM YourTable AS T1
INNER JOIN
(SELECT user_id , MIN(some_timestamp) AS some_timestamp FROM YourTable
GROUP BY user_id) AS T2
ON T1.User_Id = T2.User_Id AND T1.some_timestamp = T2.some_timestamp
WHERE Some_Timestamp BETWEEN '13-Jun-12 08:00' AND '13-Jun-12 10:00'
表名:YourTable
| PK_ID | USER_ID | SOME_TIMESTAMP |
------------------------------------|
| 1 | 123 | 13-Jun-12 14:30 |
| 2 | 123 | 13-Jun-12 08:50 |
| 3 | 567 | 13-Jun-12 09:23 |
| 4 | 567 | 13-Jun-12 09:45 |
| 5 | 567 | 13-Jun-12 09:40 |
| 6 | 890 | 13-Jun-12 08:44 |
我想得的是这样的1。从[13-Jun-12 08:00]之间的特定日期范围获取数据[13-Jun-12 10:00]
2。一旦它在范围内获取日期,它将获取没有重复的最新日期。
输出应该是这样的:
1.日期范围
[13-Jun-12 08:00] & [13-Jun-12 10:00]
结果应该是这样的
| PK_ID | USER_ID | SOME_TIMESTAMP |
------------------------------------|
| 2 | 123 | 13-Jun-12 08:50 |
| 4 | 567 | 13-Jun-12 09:45 |
| 6 | 890 | 13-Jun-12 08:44 |
非常感谢大家!
答案 0 :(得分:4)
SELECT
pk_id,
user_id,
MAX(some_timestamp)
FROM
your_table
WHERE
some_timestamp>= '13-Jun-12 08:00'
AND some_timestamp<= '13-Jun-12 10:00'
GROUP BY
user_id
ORDER BY
pk_id ASC
答案 1 :(得分:1)
您的查询非常接近。需要选择MAX
而不是MIN
,并且需要将WHERE
条件移到子查询中:
SELECT *
FROM YourTable AS T1
INNER JOIN
(SELECT user_id , MAX(some_timestamp) AS some_timestamp
FROM YourTable
WHERE Some_Timestamp BETWEEN '2013-06-12 08:00' AND '2013-06-12 10:00'
GROUP BY user_id) AS T2
ON T1.User_Id = T2.User_Id AND T1.some_timestamp = T2.some_timestamp
返回:
PK_ID USER_ID SOME_TIMESTAMP
2 123 June, 12 2013 08:50
4 567 June, 12 2013 09:45
6 890 June, 12 2013 08:44
根据需要格式化SOME_TIMESTAMP
字段。我还建议您使用>=
和<=
代替BETWEEN
,因为您可能无法通过BETWEEN
获得所需的结果。
答案 2 :(得分:0)
我想你在最大时间戳时想要pk_id
。
要在MySQL中执行此操作,您通常必须重新加入原始数据。但在您的情况下,似乎pk_id正在增加以增加时间戳。如果这是真的,那么以下查询应返回您想要的内容:
select max(pk_id) as pk_id, user_id, max(some_timestamp)
FROM your_table
WHERE Some_Timestamp between '13-Jun-12 08:00' AND Some_Timestamp <= '13-Jun-12 10:00'
GROUP BY user_id
ORDER BY pk_id ASC
如果您不包含max(pk_id)
,则会返回任意pk_id
,这与最大时间戳无关。