继承我的代码后,评论总结了该计划的目的。
// This program will read in from a file a number that tells how many
// wages and hours worked the file contain. And then calculates the
// salary
import java.util.*;
import java.text.*;
public class Lab10
{
public static void main(String[] args)
{
// Declare variables
Scanner scan = new Scanner(System.in);
DecimalFormat fmt = new DecimalFormat("0.00");
String name;
double wages;
double hoursWorked;
double salary;
int numCalculate;
int EmployeeNumber ;
int i = 0 ;
// Read in how many employees the file contains
EmployeeNumber =scan.nextInt() ;
// for loop that reads and records the name hoursworked and wages , and prints out the information
for ( ; i < EmployeeNumber +1; i ++ )
{
name = scan.next () ;
wages = scan.nextDouble() ;
hoursWorked = scan.nextDouble() ;
salary = calculateSalary(wages,hoursWorked) ;
System.out.println(name +" worked " +fmt.format(hoursWorked) + " with a wage of " + "$" +fmt.format(wages) + " and got paid $" +fmt.format(salary) );
}
// End of control loop
} // End of main method
public static double calculateSalary(double wages, double hoursWorked)
{
//Declare constants
final int OVERTIME_BREAK = 40;
final double OVERTIME_MULTIPLE = 1.5;
double salary = 0 ;
//Calculate salary
if(hoursWorked > OVERTIME_BREAK)
{
salary = (hoursWorked - OVERTIME_BREAK) * wages * OVERTIME_MULTIPLE + hoursWorked * wages;
}
else
{
salary = hoursWorked * wages;
}
// Return the salary
return salary ;
} // end of calculateSalary method
} // End of Lab10 class
使用此输入文件时:
3
Smith 12.50 25
Jones 25.89 60
Brown 7.86 19.89
我得到了我想要的输出,但是这个消息在最后得到了解释:
Exception in thread "main" java.util.NoSuchElementException
at java.util.Scanner.throwFor(Scanner.java:855)
at java.util.Scanner.next(Scanner.java:1364)
at Lab10.main(Lab10.java:32)
有人可以告诉我这意味着什么以及如何解决它?
答案 0 :(得分:2)
你循环太多次了。
你有3名员工,因此应该像这样循环:
for ( ; i < EmployeeNumber; i ++ )
{
name = scan.next () ;
...
}
答案 1 :(得分:0)
Java的数组索引从0开始,所以如果你有3个元素,那么它们存储在0,1和2中。如上所述,在你的for循环中,如果你只是把i&lt; EmplyeeNumber足够,而不是EmployeeNumber + 1。