原始问题
所以我不熟悉编码。我可能已经打了3个月大关。但我喜欢通过我正在上课,因为这些东西真的让我感兴趣。所以我想搞砸一些代码来尝试更多地理解它。经过大量的谷歌搜索,这是我已经得到的。该程序假设要求输入密码。如果输入了正确的密码,则会显示两个选项。选项1将让您输入信息(姓名,姓氏,年龄,手机号码)。选项2将显示存储的信息。到目前为止,除了我希望将从A中获得的信息显示为B之外,其他所有事情都变得很好。我有两个单独的类。 第一个被称为main(这是主要方法,巫婆工作正常)
import javax.swing.*;
//Created by: Robert Duval
//3/26/13
public class Main
{
public static void main(String[] args)
{
String tempString, passWord = "mrGiggles", input = "null";
while(!input.equals(passWord)) //This loop looks for the password
{
input = JOptionPane.showInputDialog("Hello, please enter password.");
if(input.equals(passWord)) //If the password is correct
{
while(!input.equals("Enter information")||!input.equals("View profile")) //This loop looks to see what to do next
{
input = JOptionPane.showInputDialog("Welcome\nEnter information\nView profile");
if(input.equals("Enter information"))
{
display.input();
}
else if(input.equals("View profile"))
{
display.stored();
}
else
{
tempString = "ERROR\nCannot find what you are looking for.";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
else //If the password is incorrect.
{
tempString = "In-correct";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
}
我的第二课(显示)是我遇到问题的地方。我应该把它们变成公共字符串吗?或者是什么? input()方法填充我想在stored()方法中使用的字符串。而且我已经看了一段时间,但我不明白回报,什么不是。如果你可以帮助我,并指出我的缺点将是太棒了。
import javax.swing.*;
//Created by: Robert Duval
//3/26/13
public class display
{
public static void input() //This is the method that will ask for the information
{
String age="null", cellNumber="null", name="null", lastName="mull", allInfo = name+ "\n" +lastName+ "\n" +age+ "\n" +cellNumber+ "\n";
name = JOptionPane.showInputDialog("Enter the first name");
lastName = JOptionPane.showInputDialog("Enter the last name");
age = JOptionPane.showInputDialog("Enter the age");
cellNumber = JOptionPane.showInputDialog("Enter the cell phone number");
display.stored();
}
public static void stored() //This method is asking the user what to show for the input() method.
{
String loop = "loop", tempString;
while(!loop.equals("break"))
{
tempString = JOptionPane.showInputDialog("What information would you like to see? \nname\nage\ncell number\nall info\nquit");
if(tempString.equals("name")||tempString.equals("Name")||tempString.equals("NAME"))
{
JOptionPane.showMessageDialog(null, name); //This is where I want to display the name String from input() method
}
else if(tempString.equals("age")||tempString.equals("Age")||tempString.equals("AGE"))
{
JOptionPane.showMessageDialog(null, age); //This is where I want to display the age String from input() method
}
else if(tempString.equals("cell number")||tempString.equals("Cell number")||tempString.equals("cell Number")||tempString.equals("Cell Number")||tempString.equals("cellNumber")||tempString.equals("cellnumber")||tempString.equals("Cellnumber"))
{
JOptionPane.showMessageDialog(null, cellNumber); //This is where I want to display the cellNumber String from input() method
}
else if(tempString.equals("all info")||tempString.equals("All info")||tempString.equals("all Info")||tempString.equals("All Info")||tempString.equals("allinfo")||tempString.equals("allInfo")||tempString.equals("Allinfo")||tempString.equals("AllInfo"))
{
JOptionPane.showMessageDialog(null, allInfo); //This is where I want to display the allInfo String from input() method
}
else if(tempString.equals("quit")||tempString.equals("Quit")||tempString.equals("QUIT"))
{
loop = "break"; //Breaks the while loop
}
else
{
tempString = "Not a valid answer. \nPlease try again.";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
}
更新的问题
好的,看完答案之后我就非常接近!但出于某种原因,当我去查看数据时,它会为所有内容产生“空”。我在想它,因为我关闭了方法,然后重新打开它,所以一切都刷新了。 如何保存输入信息。离开方法。回来但是打开显示并显示该信息?
以下是更新后的代码:
主要课程
import javax.swing.*;
//Created by Robert Duval
//3/26/13
public class Main
{
public static void main(String[] args)
{
String tempString, passWord = "mrGiggles", input = "null";
display display = new display();
while(!input.equals(passWord)) //This loop looks for the password
{
input = JOptionPane.showInputDialog("Hello, please enter password.");
if(input.equals(passWord)) //If the password is correct
{
while(!input.equalsIgnoreCase("Enter information")||!input.equalsIgnoreCase("View profile")) //This loop looks to see what to do next
{
input = JOptionPane.showInputDialog("Welcome\nEnter information\nView profile");
if(input.equalsIgnoreCase("Enter information"))
{
display.input();
}
else if(input.equalsIgnoreCase("View profile"))
{
display.stored();
}
else
{
tempString = "ERROR\nCannot find what you are looking for.";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
else //If the password is incorrect.
{
tempString = "In-correct";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
}
显示课程
import javax.swing.*;
//Created by: Robert Duval
//3/26/13
public class display
{
String age="null", cellNumber="null", name="null", lastName="mull", allInfo = name+ "\n" +lastName+ "\n" +age+ "\n" +cellNumber+ "\n";
public void input()
{
name = JOptionPane.showInputDialog("Enter the first name");
lastName = JOptionPane.showInputDialog("Enter the last name");
age = JOptionPane.showInputDialog("Enter the age");
cellNumber = JOptionPane.showInputDialog("Enter the cell phone number");
}
public void stored()
{
String tempString;
while(true)
{
tempString = JOptionPane.showInputDialog("What information would you like to see? \nname\nage\ncell number\nall info\nquit");
if (tempString.equalsIgnoreCase("name"))
{
JOptionPane.showMessageDialog(null, name); //This is where I want to display the name String from input() method
}
else if(tempString.equalsIgnoreCase("age"))
{
JOptionPane.showMessageDialog(null, age); //This is where I want to display the age String from input() method
}
else if(tempString.equalsIgnoreCase("cell number"))
{
JOptionPane.showMessageDialog(null, cellNumber); //This is where I want to display the cellNumber String from input() method
}
else if(tempString.equalsIgnoreCase("all info")||tempString.equalsIgnoreCase("allinfo"))
{
JOptionPane.showMessageDialog(null, allInfo); //This is where I want to display the allInfo String from input() method
}
else if(tempString.equalsIgnoreCase("quit"))
{
break; //Breaks the while loop
}
else
{
tempString = "Not a valid answer. \nPlease try again.";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
}
BTW感谢所有人的帮助。我很感激。
解决方案
好吧,伙计们。我玩了一些它,并找到了如何让它工作。感谢您需要的所有帮助。
主要课程
import javax.swing.*;
//Created by Robert Duval
//3/26/13
public class Main
{
public static void main(String[] args)
{
String tempString, passWord = "mrGiggles", input = "null";
display display = new display();
while(!input.equals(passWord)) //This loop looks for the password
{
input = JOptionPane.showInputDialog("Hello, please enter password.\nQuit");
if(input.equals(passWord)) //If the password is correct
{
while(!input.equalsIgnoreCase("Enter information")||!input.equalsIgnoreCase("View profile")) //This loop looks to see what to do next
{
input = JOptionPane.showInputDialog("Welcome\nEnter information\nView profile\nLog out");
if(input.equalsIgnoreCase("Enter information"))
{
display.input();
}
else if(input.equalsIgnoreCase("View profile"))
{
display.stored();
}
else if(input.equalsIgnoreCase("log out"))
{
break;
}
else
{
tempString = "ERROR\nCannot find what you are looking for.";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
else if(input.equalsIgnoreCase("quit"))
{
break;
}
else //If the password is incorrect.
{
tempString = "In-correct";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
}
显示课程
import javax.swing.*;
//Created by: Robert Duval
//3/26/13
public class display
{
String age="null", cellNumber="null", name="null", lastName="null";
public void input()
{
name = JOptionPane.showInputDialog("Enter the first name");
lastName = JOptionPane.showInputDialog("Enter the last name");
age = JOptionPane.showInputDialog("Enter the age");
cellNumber = JOptionPane.showInputDialog("Enter the cell phone number");
}
public void stored()
{
String tempString, allInfo = name+ "\n" +lastName+ "\n" +age+ "\n" +cellNumber+ "\n";
while(true)
{
tempString = JOptionPane.showInputDialog("What information would you like to see? \nName\nAge\nCell number\nAll info\nBack");
if (tempString.equalsIgnoreCase("name"))
{
JOptionPane.showMessageDialog(null, name);
}
else if(tempString.equalsIgnoreCase("age"))
{
JOptionPane.showMessageDialog(null, age);
}
else if(tempString.equalsIgnoreCase("cell number"))
{
JOptionPane.showMessageDialog(null, cellNumber);
}
else if(tempString.equalsIgnoreCase("all info")||tempString.equalsIgnoreCase("allinfo"))
{
JOptionPane.showMessageDialog(null, allInfo);
}
else if(tempString.equalsIgnoreCase("back"))
{
break;
}
else
{
tempString = "Not a valid answer. \nPlease try again.";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
}
它完美运行!
P.S 它不会让我回答我自己的问题
答案 0 :(得分:0)
您需要使您的显示类方法非静态,并使用带有字段的对象:
public class Display
{
private String age="null", cellNumber="null", name="null", lastName="mull", allInfo = name+ "\n" +lastName+ "\n" +age+ "\n" +cellNumber+ "\n";
public void input()
{
name = JOptionPane.showInputDialog("Enter the first name");
lastName = JOptionPane.showInputDialog("Enter the last name");
age = JOptionPane.showInputDialog("Enter the age");
cellNumber = JOptionPane.showInputDialog("Enter the cell phone number");
stored();
}
public void stored()
{
String tempString;
while(true)
{
tempString = JOptionPane.showInputDialog("What information would you like to see? \nname\nage\ncell number\nall info\nquit");
if(tempString.equalsIgnoreCase("name"))
{
JOptionPane.showMessageDialog(null, name); //This is where I want to display the name String from input() method
}
else if(tempString.equalsIgnoreCase("age"))
{
JOptionPane.showMessageDialog(null, age); //This is where I want to display the age String from input() method
}
else if(tempString.equalsIgnoreCase("cell number")||tempString.equals("Cell number")||tempString.equalsIgnoreCase("cellNumber"))
{
JOptionPane.showMessageDialog(null, cellNumber); //This is where I want to display the cellNumber String from input() method
}
else if(tempString.equalsIgnoreCase("all info")||tempString.equalsIgnoreCase("allinfo"))
{
JOptionPane.showMessageDialog(null, allInfo); //This is where I want to display the allInfo String from input() method
}
else if(tempString.equalsIgnoreCase("quit"))
{
break; //Breaks the while loop
}
else
{
tempString = "Not a valid answer. \nPlease try again.";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
}
如你所见,我将班级名称从display
更改为Display
。这是一种Java变体,用于从变量名中分散类名。这些方法不再是静态的,这意味着你不能在类上调用它们,而只能在该类的对象上调用它们。这样的对象可以有描述它的条件的字段。要访问这些字段,您需要非静态成员。调用display.stored()
现在只需stored()
即可在您刚刚调用input()
的同一对象上调用该方法。要清除它,您还可以编写this.stored()
。 this
始终指向当前对象。
我还在break
类的循环中引入了Display
命令。
让我们来看看现在主要课程要做出哪些改变:
public class Main
{
public static void main(String[] args)
{
String tempString, passWord = "mrGiggles", input = "null";
Display display = new Display();
while(!input.equals(passWord)) //This loop looks for the password
{
input = JOptionPane.showInputDialog("Hello, please enter password.");
if(input.equals(passWord)) //If the password is correct
{
while(!input.equals("Enter information")||!input.equals("View profile")) //This loop looks to see what to do next
{
input = JOptionPane.showInputDialog("Welcome\nEnter information\nView profile");
if(input.equals("Enter information"))
{
display.input();
}
else if(input.equals("View profile"))
{
display.stored();
}
else
{
tempString = "ERROR\nCannot find what you are looking for.";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
else //If the password is incorrect.
{
tempString = "In-correct";
JOptionPane.showMessageDialog(null, tempString);
}
}
}
}
行Display display = new Display()
创建Display
类的新对象,并将其分配给类型为Display
且名称为display
的变量。如果在display
(现在是变量)上调用方法,则会在变量指向的对象上调用它们而不是类。