Question

      <%@ Page Language="C#" AutoEventWireup="true" CodeFile="test.aspx.cs"  Inherits="test"%>

      <%@ Register assembly="AjaxControlToolkit" namespace="AjaxControlToolkit" tagprefix="asp" %>

       <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"    "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

      <html xmlns="http://www.w3.org/1999/xhtml">
       <head runat="server">
       <title></title>
      </head>
      <body style="height: 162px">
<form id="form1" runat="server">
<div>

    <asp:RadioButton ID="MCA" runat="server" Text="MCA" AutoPostBack="True" 
        oncheckedchanged="MCA_CheckedChanged" />
    <br />

</div>
<asp:DropDownList ID="DropDownList1" runat="server" AutoPostBack="True">
    <asp:ListItem Value="Sem1"></asp:ListItem>
    <asp:ListItem Value="Sem2"></asp:ListItem>
</asp:DropDownList>
<br />
<asp:DropDownList ID="DropDownList2" runat="server" AutoPostBack="True" 
    onselectedindexchanged="DropDownList2_SelectedIndexChanged" 
    ViewStateMode="Enabled">
    <asp:ListItem Value="MCA101"></asp:ListItem>
    <asp:ListItem Value="MCA103">MCA103</asp:ListItem>
</asp:DropDownList>
<br />
<asp:ScriptManager ID="ScriptManager1" runat="server">
</asp:ScriptManager>
<br />

<asp:UpdatePanel ID="UpdatePanel1" runat="server">
    <ContentTemplate>
     <br />
        <asp:AjaxFileUpload ID="AjaxFileUpload1" runat="server" 
            OnUploadComplete="upload"/>
    <br />
    </ContentTemplate>
</asp:UpdatePanel>
</form>
</body>
</html>

活动代码..

      protected void upload(Object sender, AjaxControlToolkit.AjaxFileUploadEventArgs e)
      {
        string s = DropDownList1.SelectedValue;
        string t = DropDownList2.SelectedValue;
        string path= string path = Server.MapPath("~/MCA/" + s + "/" +t+ "/")+e.FileName 
      }

//即使选择了其他值并且未按照直接结构进行上传，s和t也会得到Dropdownlist的第一个值。

两个Dropdownlist都有多个值，回发属性对于这两个列表都是true。

如何获得精确选择的列表值？

Answer 1

调用AjaxFileUpload OnUploadComplete事件时，问题为Request.Form["__VIEWSTATE"] = null。

修复此问题（C＃代码）：

在页面加载时设置会话中的下拉选择。

protected void Page_Load(object sender, EventArgs e)
{
 if (Request.Form["__VIEWSTATE"] != null)
    Session["Path"] = "//" + DropDownList1.SelectedValue + "//" + DropDownList2.SelectedValue + "//";
}

使用会话值创建文件路径：

protected void upload(Object sender, AjaxControlToolkit.AjaxFileUploadEventArgs e)
{
        string path = string.Empty;
        if (Session["Path"] != null)
            path = Server.MapPath("~//MCA" + (string)Session["Path"]) + e.FileName;
}

Answer 2

我相信您需要将下拉列表添加到与上传控件相同的更新面板中。

如何在AjaxFileUpload onuploadComplete事件中获取选定的dropdownvalue？

2 个答案: