我正在尝试编写自己的时区转换器,我需要一种方法来确定本月的最后一天。通过一些研究,我发现了寻找闰年的公式。
这是一个小小的贡献,但也许我会在20分钟内拯救别人,让我弄明白并应用它。
此代码接受签名的短月,索引为0(0表示1月),并且int年也被索引为0(2012年是2012年)。
它返回1个索引日(27日是27日,但在SYSTEMTIME结构中,你通常需要0索引 - 只是抬头)。
答案 0 :(得分:4)
short _get_max_day(short month, int year) {
if(month == 0 || month == 2 || month == 4 || month == 6 || month == 7 || month == 9 || month == 11)
return 31;
else if(month == 3 || month == 5 || month == 8 || month == 10)
return 30;
else {
if(year % 4 == 0) {
if(year % 100 == 0) {
if(year % 400 == 0)
return 29;
return 28;
}
return 29;
}
return 28;
}
}
答案 1 :(得分:3)
怎么样?
#include <time.h>
#include <iostream>
int LastDay (int iMonth, int iYear)
{
struct tm when;
time_t lastday;
// Set up current month
when.tm_hour = 0;
when.tm_min = 0;
when.tm_sec = 0;
when.tm_mday = 1;
// Next month 0=Jan
if (iMonth == 12)
{
when.tm_mon = 0;
when.tm_year = iYear - 1900 + 1;
}
else
{
when.tm_mon = iMonth;
when.tm_year = iYear - 1900;
}
// Get the first day of the next month
lastday = mktime (&when);
// Subtract 1 day
lastday -= 86400;
// Convert back to date and time
when = *localtime (&lastday);
return when.tm_mday;
}
int _tmain(int argc, _TCHAR* argv[])
{
for (int m = 1; m <= 12; m++)
std::cout << "Last day of " << m << " is " << LastDay (m, 2002) << std::endl;
return 0;
}
打印出来(2002年)......
Last day of 1 is 31
Last day of 2 is 28
Last day of 3 is 31
Last day of 4 is 30
Last day of 5 is 31
Last day of 6 is 30
Last day of 7 is 31
Last day of 8 is 31
Last day of 9 is 30
Last day of 10 is 31
Last day of 11 is 30
Last day of 12 is 31
答案 2 :(得分:0)
我使用一个简单的函数,它返回(标准)COleDateTime的整个日期。它可能不是那么快的其他选择,但它非常有效,适用于闰年和非常简单的证据。
这是我正在使用的代码:
COleDateTime get_last_day_of_month(UINT month, UINT year)
{
if(month == 2)
{ // if month is feb, take last day of March and then go back one day
COleDateTime date(year, 3, 1, 0, 0, 0); // 1 March for Year
date -= 1; // go back one day (the standard class will take leap years into account)
return date;
}
else if(month == 4 || month == 6 || month == 9 || month == 11) return COleDateTime(year, month, 30, 0, 0, 0);
else return COleDateTime(year, month, 31, 0, 0, 0);
}
答案 3 :(得分:-1)
Word Year, Month, Day;
TDateTime datum_tdatetime = Date();
// first day of actual month
datum_tdatetime.DecodeDate(&year, &month, &day);
day = 1;
datum_tdatetime = EncodeDate(year, month, day);
// last day of previous month
datum_tdatetime -= 1;
// first day of previous month
datum_tdatetime.DecodeDate(&year, &month, &day);
day = 1;
datum_tdatetime = EncodeDate(year, month, day);