Question

我在extjs + yii工作。我有观点 -

Ext.define('Balaee.view.qb.qbqns.QbqnsView',
{
        extend:'Ext.view.View',
        id:'qbqnsViewId',
        alias:'widget.QbqnsView',
        store:'qb.QbqnsStore',
        autoScroll: true,
        config:
        {
            tpl:'<tpl for=".">'+
                '<div id="main">'+
                '</br>'+
            //  '<b>Question :-</b> {pollQuestion}</br>'+
                '<h1 id="q">Question :-</h1> {question} </br>'+

                '<tpl for="options">'+     // interrogate the kids property within the data
                 '<p>&nbsp&nbsp<input type="radio" name="{parent.questionId}" value="{optionId}">&nbsp{option}</p>'+
                //'<p>&nbsp&nbsp<input type="radio" name="{questionId}">&nbsp{option}</p>'+
                '</tpl></p>'+
                '<p>---------------------------------------------------------</p>'+
                '</div>'+
                '</tpl>',
            itemSelector:'div.main' 
        }
});// End of login class

此视图显示问题及其相关选项。现在选择答案并单击提交按钮后，我想发送Questionid及其选中的单选按钮选项。由于数据采用json的格式，我正在捕获这些选定的单选按钮值，制作jsons并在此之后将其作为参数传递。所以在控制器中我编写了代码 -

var answers = '{"data":[';
        var i=0;
        QbqnsStore.each(function(model){
            i++;
            var inputs = document.getElementsByName(model.get('questionId'));
            console.log(document.getElementsByName(model.get('questionId')));
            console.log("length is"+inputs.length);
            for (var j = 0; j < inputs.length; j++) {
                if (inputs[j].checked) {
                    console.log("count of store is"+QbqnsStore.count());
                    //if (i == QbqnsStore.count()){
                    if (i == QbqnsStore.count()){
                        console.log("value of i is"+i);
                        answers = answers + '{"paperId":"'+paperNumber+'","userId":"'+userId+'","questionId":"'+inputs[j].name+'","option":'+inputs[j].value+'}'
                    //i=1;
                    }
                    else{
                        console.log("value of i is"+i);
                        answers = answers + '{"paperId":"'+paperNumber+'","userId":"'+userId+'","questionId":"'+inputs[j].name+'","option":'+inputs[j].value+'},'
                    }
                }
            }// End of inner for loop
        }); //End of each

        answers =answers+']}';
        console.log("selected data is:");
        console.log(answers);
        var storeObject=this.getStore('qb.QbquestionoptionStore');
        storeObject.load({

            params:{
                data: answers 
            },
            callback: function(records,operation,success){

            },
            scope:this
        });

当用户解决所有问题时，它正常工作。在解决所有问题的情况下，上述函数正在形成json为 -

{"data":[{"paperId":"1517","userId":"116","questionId":"1","option":1},{"paperId":"1517","userId":"116","questionId":"2","option":4},{"paperId":"1517","userId":"116","questionId":"3","option":9},{"paperId":"1517","userId":"116","questionId":"4","option":9}]}

格式正确。但是当用户只从纸上解决前一个或两个问题时，它就形成了json -

{"data":[{"paperId":"1518","userId":"116","questionId":"2","option":4},]}

即。在json的末尾插入额外的逗号，这使得json无效。所以当用户只解决一个或两个问题时，如何从json中删除这个额外的逗号。请指导我

Answer 1

我认为你的情况永远不会成真。你试过了吗？

if (i == QbqnsStore.count() - 1){

而不是

if (i == QbqnsStore.count()){

在extjs中如何进行验证json

1 个答案: