我有一个返回JSON对象的URL,如下所示:
{
"expires_in":5180976,
"access_token":"AQXzQgKTpTSjs-qiBh30aMgm3_Kb53oIf-VA733BpAogVE5jpz3jujU65WJ1XXSvVm1xr2LslGLLCWTNV5Kd_8J1YUx26axkt1E-vsOdvUAgMFH1VJwtclAXdaxRxk5UtmCWeISB6rx6NtvDt7yohnaarpBJjHWMsWYtpNn6nD87n0syud0"
}
我想获得access_token
值。那么如何通过PHP检索它?
答案 0 :(得分:317)
$json = file_get_contents('url_here');
$obj = json_decode($json);
echo $obj->access_token;
为此,file_get_contents
要求启用allow_url_fopen
。这可以在运行时通过包括:
ini_set("allow_url_fopen", 1);
您还可以使用curl
获取网址。要使用curl,您可以使用找到的示例here:
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'url_here');
$result = curl_exec($ch);
curl_close($ch);
$obj = json_decode($result);
echo $obj->access_token;
答案 1 :(得分:25)
$url = 'http://.../.../yoururl/...';
$obj = json_decode(file_get_contents($url), true);
echo $obj['access_token'];
Php也可以使用带破折号的属性:
garex@ustimenko ~/src/ekapusta/deploy $ psysh
Psy Shell v0.4.4 (PHP 5.5.3-1ubuntu2.6 — cli) by Justin Hileman
>>> $q = new stdClass;
=> <stdClass #000000005f2b81c80000000076756fef> {}
>>> $q->{'qwert-y'} = 123
=> 123
>>> var_dump($q);
class stdClass#174 (1) {
public $qwert-y =>
int(123)
}
=> null
答案 2 :(得分:13)
您可以使用PHP的json_decode功能:
$url = "http://urlToYourJsonFile.com";
$json = file_get_contents($url);
$json_data = json_decode($json, true);
echo "My token: ". $json_data["access_token"];
答案 3 :(得分:7)
// Get the string from the URL
$json = file_get_contents('https://maps.googleapis.com/maps/api/geocode/json?latlng=40.714224,-73.961452');
// Decode the JSON string into an object
$obj = json_decode($json);
// In the case of this input, do key and array lookups to get the values
var_dump($obj->results[0]->formatted_address);
答案 4 :(得分:6)
您需要阅读有关json_decode函数http://php.net/manual/en/function.json-decode.php
的内容你去吧
$json = '{"expires_in":5180976,"access_token":"AQXzQgKTpTSjs-qiBh30aMgm3_Kb53oIf-VA733BpAogVE5jpz3jujU65WJ1XXSvVm1xr2LslGLLCWTNV5Kd_8J1YUx26axkt1E-vsOdvUAgMFH1VJwtclAXdaxRxk5UtmCWeISB6rx6NtvDt7yohnaarpBJjHWMsWYtpNn6nD87n0syud0"}';
//OR $json = file_get_contents('http://someurl.dev/...');
$obj = json_decode($json);
var_dump($obj-> access_token);
//OR
$arr = json_decode($json, true);
var_dump($arr['access_token']);
答案 5 :(得分:3)
$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, 'url_here');
$result = curl_exec($ch);
curl_close($ch);
$obj = json_decode($result);
echo $obj->access_token;
答案 6 :(得分:2)
file_get_contents()
没有从网址获取数据,然后我尝试了curl
并且工作正常。
答案 7 :(得分:1)
我的解决方案仅适用于以下情况: 如果您将一个多维数组误认为一个数组
$json = file_get_contents('url_json'); //get the json
$objhigher=json_decode($json); //converts to an object
$objlower = $objhigher[0]; // if the json response its multidimensional this lowers it
echo "<pre>"; //box for code
print_r($objlower); //prints the object with all key and values
echo $objlower->access_token; //prints the variable
我知道答案已经被回答了,但是对于那些来这里找东西的人,希望对您有所帮助
答案 8 :(得分:0)
使用curl
时有时会给您403(禁止访问)
通过添加此行来模拟浏览器来解决。
curl_setopt($ch, CURLOPT_USERAGENT, 'Mozilla/4.0 (compatible; MSIE 6.0; Windows NT 5.1; SV1; .NET CLR 1.0.3705; .NET CLR 1.1.4322)');
希望这对某人有所帮助。
答案 9 :(得分:0)
我们的解决方案,在响应中添加了一些验证,因此我们确定我们在 $ json 变量
中具有格式正确的json对象$ch = curl_init();
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_URL, $url);
$result = curl_exec($ch);
curl_close($ch);
if (! $result) {
return false;
}
$json = json_decode(utf8_encode($result));
if (empty($json) || json_last_error() !== JSON_ERROR_NONE) {
return false;
}
答案 10 :(得分:0)
$curl_handle=curl_init();
curl_setopt($curl_handle, CURLOPT_URL,'https://www.xxxSite/get_quote/ajaxGetQuoteJSON.jsp?symbol=IRCTC&series=EQ');
//Set the GET method by giving 0 value and for POST set as 1
//curl_setopt($curl_handle, CURLOPT_POST, 0);
curl_setopt($curl_handle, CURLOPT_CUSTOMREQUEST, "GET");
curl_setopt($curl_handle, CURLOPT_CONNECTTIMEOUT, 2);
curl_setopt($curl_handle, CURLOPT_RETURNTRANSFER, 1);
$query = curl_exec($curl_handle);
$data = json_decode($query, true);
curl_close($curl_handle);
//print complete object, just echo the variable not work so you need to use print_r to show the result
echo print_r( $data);
//at first layer
echo $data["tradedDate"];
//Inside the second layer
echo $data["data"][0]["companyName"];
有时候您可能会得到405,请正确设置方法类型。