您好我选择并且效果很好:
select 'CARAT Issue Open' issue_comment, i.issue_id, i.issue_status, i.issue_title, i.ISSUE_summary ,i.issue_description, i.severity,
gcrs.Area_name, gcrs.sector_name,
substr(gcrs.stream_name,1,case when instr(gcrs.stream_name,' (')=0 then 100 else instr(gcrs.stream_name,' (')-1 end) ISSUE_DIVISION,
case when gcrs.STREAM_NAME like 'NON-GT%' THEN 'NON-GT' ELSE gcrs.STREAM_NAME END as ISSUE_DIVISION_2
from table(f_carat_issues_as_of('31/MAR/2013')) i
inner join v_gcrs_with_stream gcrs on i.segment_id = gcrs.segment_id
where UPPER(ISSUE_STATUS) like '%OPEN%'
现在我想调用两列: ISSUE_DIVISION和ISSUE_DIVISION_2
如果它们在新列中相等则值为1如果不相等则应为0,
我该怎么办?
我的完整代码:
select 'CARAT Issue Open' issue_comment, i.issue_id, i.issue_status, i.issue_title, i.ISSUE_summary ,i.issue_description, i.severity,
gcrs.Area_name, gcrs.sector_name,
substr(gcrs.stream_name,1,case when instr(gcrs.stream_name,' (')=0 then 100 else instr(gcrs.stream_name,' (')-1 end) ISSUE_DIVISION,
case when gcrs.STREAM_NAME like 'NON-GT%' THEN 'NON-GT' ELSE gcrs.STREAM_NAME END as ISSUE_DIVISION_2
from table(f_carat_issues_as_of('31/MAR/2013')) i
inner join v_gcrs_with_stream gcrs on i.segment_id = gcrs.segment_id
where UPPER(ISSUE_STATUS) like '%OPEN%' and
CASE WHEN ISSUE_DIVISION = ISSUE_DIVISION_2 THEN
CASE WHEN ISSUE_DIVISION is null then "Null Value found"
Else 1 End
ELSE 0 END As Issue_Division_Result
但我在网上收到错误: ELSE 0 END作为Issue_Division_Result
ORA-00920:无效的关系运算符:(
答案 0 :(得分:51)
SELECT (CASE WHEN ISSUE_DIVISION = ISSUE_DIVISION_2 THEN 1 ELSE 0 END) AS ISSUES
-- <add any columns to outer select from inner query>
FROM
( -- your query here --
select 'CARAT Issue Open' issue_comment, ...., ...,
substr(gcrs.stream_name,1,case when instr(gcrs.stream_name,' (')=0 then 100 else instr(gcrs.stream_name,' (')-1 end) ISSUE_DIVISION,
case when gcrs.STREAM_NAME like 'NON-GT%' THEN 'NON-GT' ELSE gcrs.STREAM_NAME END as ISSUE_DIVISION_2
from ....
where UPPER(ISSUE_STATUS) like '%OPEN%'
)
WHERE... -- optional --
答案 1 :(得分:10)
这么简单,你可以在这里使用 case 语句。
CASE WHEN ISSUE_DIVISION = ISSUE_DIVISION_2 THEN
CASE WHEN ISSUE_DIVISION is null then "Null Value found" //give your option
Else 1 End
ELSE 0 END As Issue_Division_Result
答案 2 :(得分:0)
使用该变量,Oracle在没有INTO的情况下不支持SQL。使用正确命名的变量,无论如何,您的代码将更加清晰。
答案 3 :(得分:0)
在一行中,答案如下;
[当COLUMN_NAME ='VALUE'然后以'SHOW_THIS'否则为'SHOW_OTHER'结束时使用别名的情况]