设置DateFormatter

时间:2013-03-25 09:44:00

标签: ios nsdateformatter

我有一些像这样的代码:

NSString *dateStr = @"23 03 2013";
NSDateFormatter *df1 = [[NSDateFormatter alloc] init];
[df1 setDateFormat:@"d MM yyyy"];
NSDate *date1 = [df1 dateFromString:dateStr];
NSDateFormatter *df2 = [[NSDateFormatter alloc] init];
[df2 setDateFormat:@"MMMM d YYYY"];
NSString *s = [df2 stringFromDate:date1];
NSLog(@"my new Date is %@",s);

//Output : March 23 2013

但我想这样:2013年3月23日,如何解决?

2 个答案:

答案 0 :(得分:3)

使用:

[df2 setDateFormat:@"MMMM d'rd' YYYY"];

* 注意,对于21,22,rd,th等,您需要检查使用条件然后更改格式化程序

NSString *dateStr = @"23 03 2013";
NSDateFormatter *df1 = [[NSDateFormatter alloc] init];
[df1 setDateFormat:@"d MM yyyy"];
NSDate *date1 = [df1 dateFromString:dateStr];
NSDateFormatter *df2 = [[NSDateFormatter alloc] init];

NSDateFormatter *dfDate=[NSDateFormatter new];
[dfDate setDateFormat:@"dd"];

NSCalendar *calendar = [NSCalendar currentCalendar];
NSDateComponents *components = [calendar components:NSMonthCalendarUnit|NSDayCalendarUnit fromDate:date1];


NSInteger dayValue=[components day];
/*
switch (dayValue) {
    case 1:
    case 21:
    case 31:
        [df2 setDateFormat:@"MMMM d'st' YYYY"];
        break;
    case 2:
    case 22:
        [df2 setDateFormat:@"MMMM d'nd' YYYY"];
        break;
    case 3:
    case 23:
        [df2 setDateFormat:@"MMMM d'rd' YYYY"];
        break;
    case 4:
    case 5:
    case 6:
    case 7:
    case 8:
    case 9:
    case 10:
    case 11:
    case 12:
    case 13:
    case 14:
    case 15:
    case 16:
    case 17:
    case 18:
    case 19:
    case 20:
    case 24:
    case 25:
    case 26:
    case 27:
    case 28:
    case 29:
    case 30:
        [df2 setDateFormat:@"MMMM d'th' YYYY"];
        break;

    default:
        break;
}
*/

NSArray *suffix=@[@"st",@"nd",@"rd",
              @"th",@"th",@"th",@"th",@"th",@"th",@"th",
              @"th",@"th",@"th",@"th",@"th",@"th",@"th",@"th",@"th",
              @"th",
              @"st",@"nd",@"rd",@"th",@"th",@"th",@"th",@"th",@"th",@"th",@"st"];
NSLog(@"%d",[suffix count]);

[df2 setDateFormat:[NSString stringWithFormat:@"MMMM d'%@' YYYY",suffix[dayValue - 1]]];

NSString *s = [df2 stringFromDate:date1];
NSLog(@"my new Date is %@",s);

注意:我使用了switch,你可以使用数组重构它。

现在你可以

答案 1 :(得分:1)

直接在IOS中不可用,但我使用以下代码

实现了它
NSString *dateStr = @"23 03 2013";
NSDateFormatter *df1 = [[NSDateFormatter alloc] init];
[df1 setDateFormat:@"d MM yyyy"];
NSDate *date1 = [df1 dateFromString:dateStr];
NSDateFormatter *df2 = [[NSDateFormatter alloc] init];
[df2 setDateFormat:@"MMMM d YYYY"];
NSString *s = [df2 stringFromDate:date1];

NSDateFormatter *monthDayFormatter = [[NSDateFormatter alloc] init];
[monthDayFormatter setFormatterBehavior:NSDateFormatterBehavior10_4];
[monthDayFormatter setDateFormat:@"d"];
int date_day = [[monthDayFormatter stringFromDate:date1] intValue];
NSString *suffix_string = @"|st|nd|rd|th|th|th|th|th|th|th|th|th|th|th|th|th|th|th|th|th|st|nd|rd|th|th|th|th|th|th|th|st";
NSArray *suffixes = [suffix_string componentsSeparatedByString: @"|"];
NSString *suffix = [suffixes objectAtIndex:date_day];

NSLog(@"Suffix %@",suffix);