Question

我正在学习java，现在我正在研究循环。我写了这段代码：

players[0] = new Player(1, "Paul", "Point Guard");
players[1] = new Player(24, "Bryant", "Shooting Guard");
players[2] = new Player (6, "James", "Small Foward");
players[3] = new Player (21, "Duncan", "Power Foward");
players[4] = new Player (12, "Howard", "Center"); 
players[5] = new Player (6, "Erving", "Small Foward");


public String name()
{   
    int number = readNumber(); // read in the number
    String s = "";
    for(Player player: players){
        // check if input number match with any number of the players
        if(player.numberMatches(number))        
            s += player.getName() + " ";
        else s = error();
    }
    return s;
}

error（）方法只返回“没有玩家有这个号码” 我的阵列播放器中有两个具有相同编号的玩家;当我调用name（）时，它返回“No Player has this nameErving” 我试图删除else语句，一切正常。为什么？请有人帮帮我吗？

Answer 1

因为每次玩家的号码与给定号码不匹配时，您都会重新分配s。

这在逻辑上是不正确的，并且每当玩家的号码不匹配时，有效地删除所有已找到的玩家。尝试这样的事情。

public String name()
{   
    int number = readNumber(); // read in the number
    String s = "";
    for(Player player : players){
        // check if input number match with any number of the players
        if(player.numberMatches(number))        
            s += player.getName() + " ";
    }
    return s.equals("") ? error() : s;
}

for循环在java中查找玩家数组中的玩家对象

1 个答案: