当我执行foreach()
循环时,当前数组元素的值$recipient
未在行->to($recipient)
上定义。这是为什么?
PHP代码(抛出错误)
foreach($recipients as $recipient) {
Mail::send('emails.invite', $data, function($m){
$m
->from('welcome@website.com', Auth::user()->name)
->to($recipient)
->subject('Auth::user()->name has invited you!');
});
}
错误
Notice: Undefined variable: recipient
PHP代码(无错误)
foreach($recipients as $recipient) {
echo $recipient;
}
答案 0 :(得分:3)
您错过了use
关键字。将代码更改为:
foreach($recipients as $recipient) {
Mail::send('emails.shareListing', $data, function($m) use($recipient) {
$m
->from('share@asd.com', Auth::user()->name)
->to($recipient)
->subject('Auth::user()->name has shared a listing with you!');
});
}
见this documentation - 尤其是第三个例子。引用:
闭包还可以从父作用域继承变量。必须在函数头中声明任何此类变量。
答案 1 :(得分:1)
这是因为你在函数的范围内。
假设你在这里使用PEAR包,我不明白你为什么要传递一个函数:http://pear.php.net/manual/en/package.mail.mail.send.php
如果您打算这样做,可以使用use
关键字将变量传递到函数范围:
function($m) use($recipient) {