Question

我想创建启动程序的批处理文件，20分钟后将关闭程序并重新启动它。

我对批处理文件的唯一了解是如何启动程序：

@echo off
Start [adress of application]

Answer 1

这有效：

@echo off                           //Turn off screen text messages
:loop                               //Set marker called loop, to return to
start "Wicked_Article_Creator" "C:\Wicked Article Creator\Wicked Article Creator.exe"  //Start program, with title and program path 
timeout /t 1200 >null               //Wait 20 minutes
taskkill /f /im "Image Name" >nul   //Image name, e.g. WickedArticleCreator.exe, can be found via Task Manager > Processes Tab > Image Name column (look for your program)
timeout /t 7 >null                  //Wait 7 seconds to give your prgram time to close fully - (optional)
goto loop                           //Return to loop marker

Answer 2

@echo off
:loop
start yourtarget.exe ...
timeout /t 1200 >null
taskkill /f /im yourtarget.exe >nul
goto loop

应该做的。

Answer 3

对于遇到这个老问题的人：您也可以ping到一个绝对不存在的地址，而不是timeout.exe：

ping 999.199.991.91 -n 1 -w 60000 >NUL

您可以将60000更改为您想要的任何延迟（以毫秒为单位）。

1 second = 1000

10 seconds = 10000

60 seconds = 60000

等等..

Answer 4

@echo off                           
:loop                               
timeout /t 20 >null   ( Wait for 20 seconds before kill program)            
taskkill /F /IM terminal.exe  
timeout /t 3600 >null ( wait for 1hr before returning to loop or recycle the process)           
goto loop

我使用另一个名为mt4bar的程序来监视我的应用程序，并在它们崩溃或关闭时重新启动它们

批处理文件 - 每20分钟后重启程序

4 个答案: