Question

我创建了一个存储配置值的类。

我的Config类的代码：

class Config
{
protected static $params = array();
protected static $instance;

private function __construct(array $params=NULL){
    if(!empty($params)){
        self::$params = $params;
    }
}

public static function init(array $params=NULL){
    if(!isset(self::$instance))
        self::$instance = new Config($params);
}

public static function getInstance(){
    return self::$instance;
}

public static function initialized(){
    return isset(self::$instance);
}


public static function get($name)
{
    $ref = &self::$params;
    $keys = explode('.', $name);
    foreach ($keys as $idx => $key):
        if (!is_array($ref) || !array_key_exists($key, $ref))
            return NULL;
        $ref = &$ref[$key];
    endforeach;
    return $ref;        
}

public function delete($name){
    $ref = &self::$params;
    $keys = explode('.', $name);
    foreach ($keys as $idx => $key):
        if (!is_array($ref) || !array_key_exists($key, $ref))
            return NULL;
        $ref = &$ref[$key];
    endforeach;

    unset($ref);        
}

public function set($name, $value) {

    $ref = &self::$params;
    $keys = explode('.', $name);
    foreach ($keys as $idx => $key) {
        if (!is_array($ref)) {
            return false;
            throw new Exception('key "'.implode('.', array_slice($keys, 0, $idx)).'" is not an array but '.gettype($ref));
        }
        if (!array_key_exists($key, $ref)) {
            $ref[$key] = array();
        }
        $ref = &$ref[$key];
       }


    $ref = $value;
    return true;
}

public function getAll(){
    return self::$params;
}

public function clear(){
    self::$params = array();
}

}

配置方法使用点格式：

Config::set("test.item","testdrive"); //store in class, array["test"]["item"]="testdrive"

但是，我试图创建一个删除值的方法，例如：

Config::delete("test.item");

在get和set方法中，我使用引用变量来查找正确的项目，但我不知道如何删除引用的变量。如果我使用unset($ref)，则Config::$params不受影响。

Answer 1

当您执行$ref = &$ref[$key];时，$ref将保留$ref[$key]的值（而非参考），因此最好将unset()优先于$ref[$key] 1}}将取消其引用，如下所示：

public function delete($name){
    $ref = &self::$params;
    $keys = explode('.', $name);
    foreach ($keys as $idx => $key):
        if (!is_array($ref) || !array_key_exists($key, $ref))
            return NULL;
    endforeach;

    unset($ref[$key]);        
}

取消设置引用变量

1 个答案: