Question

我正在尝试在XSL中弄清楚如何结束元素＆lt; bold＆gt;它是元素的父元素

编辑此外，元素＆lt;段落＆gt;的内容和＆lt; bold＆gt;得到一个＆lt;样式名称 =“黑体”取代。不包括＆lt; link＆gt;的内容元件。＆LT;风格＆GT;将包含在＆lt;段＆gt;的内容中和＆lt; bold＆gt;。元素的内容＆lt;段落＆gt;可以有一个或多个＆lt; bold＆gt;和＆lt; link＆gt;

输入XML

<paragraph>
     This is some text that  has no style
 </paragraph> 

 <paragraph>
     This is some text that is  <bold>correct way</bold> <link>need    
     to be linked </link> to a document
 </paragraph>

 <paragraph>
     This is some text that is  <bold>incorrect <link>need
     to be linked </link> way </bold> to a document
 </paragraph>

输出Xml 应为

<paragraph>
     This is some text that  has no style
 </paragraph> 

 <paragraph>
     <style name="bold">This is some text that is  <bold>correct way</bold></style>
     <link>need to be linked </link>
     <style name="bold"> to a document</style>
 </paragraph>

 <paragraph>
     <style name="bold">This is some text that is  <bold>incorrect</bold></style> 
     <link>need to be linked </link>
     <style name="bold"><bold> way </bold> to a document</style>
 </paragraph>

非常感谢任何帮助。

Answer 1

此转化：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="bold[link]"><xsl:apply-templates/></xsl:template>

 <xsl:template match="bold[link]/text()">
  <bold><xsl:value-of select="."/></bold>
 </xsl:template>
</xsl:stylesheet>

应用于提供的XML文档（提供的片段包装到单个顶部元素中）：

<t>
 <paragraph>
     This is some text that is  <bold>correct way</bold> <link>need
     to be linked </link> to a document
 </paragraph>

 <paragraph>
     This is some text that is  <bold>incorrect <link>need
     to be linked </link> way </bold> to a document
 </paragraph>
</t>

会产生想要的正确结果：

<t>
   <paragraph>
     This is some text that is  <bold>correct way</bold>
      <link>need
     to be linked </link> to a document
 </paragraph>
   <paragraph>
     This is some text that is  <bold>incorrect </bold>
      <link>need
     to be linked </link>
      <bold> way </bold> to a document
 </paragraph>
</t>

OP更新了问题 - 这是稍微修改后的转换，它实现了初始+新要求：

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
 <xsl:output omit-xml-declaration="yes" indent="yes"/>
 <xsl:strip-space elements="*"/>

 <xsl:template match="node()|@*">
  <xsl:copy>
   <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
 </xsl:template>

 <xsl:template match="paragraph[bold]">
  <paragraph>
    <style name="bold"><xsl:apply-templates/></style>
  </paragraph>
 </xsl:template>

 <xsl:template match="bold[link]"><xsl:apply-templates/></xsl:template>

 <xsl:template match="bold[link]/text()">
  <bold><xsl:value-of select="."/></bold>
 </xsl:template>
</xsl:stylesheet>

将此转换应用于以下文档时：

<t>
<paragraph>
     This is some text that  has no style
 </paragraph>

 <paragraph>
     This is some text that is  <bold>correct way</bold> <link>need
     to be linked </link> to a document
 </paragraph>

 <paragraph>
     This is some text that is  <bold>incorrect <link>need
     to be linked </link> way </bold> to a document
 </paragraph>
 </t>

产生了想要的正确结果：

<t>
   <paragraph>
     This is some text that  has no style
 </paragraph>
   <paragraph>
      <style name="bold">
     This is some text that is  <bold>correct way</bold>
         <link>need
     to be linked </link> to a document
 </style>
   </paragraph>
   <paragraph>
      <style name="bold">
     This is some text that is  <bold>incorrect </bold>
         <link>need
     to be linked </link>
         <bold> way </bold> to a document
 </style>
   </paragraph>
</t>

混合内容中的结束父标记

1 个答案: