Question

def shapearea():
    shape = raw_input("What shape do you want to print? ")
    if shape == "triangle" or "Triangle":
        return trianglearea()

    elif shape == "circle" or "Circle":
        return circlearea()

    elif shape == "square" or "Square":
        return squarearea()
    else:
        shapearea()

shapearea()

使用此代码会破坏我的程序，如何让程序注册（例如）：

“circle”或“Circle”为相同的

Answer 1

if shape in ("triangle", "Triangle")

或更好，

if shape.lower() == "triangle"

Answer 2

@ jamylak答案的替代方案，以下是您的需求：

if shape == "triangle" or shape == "Triangle":
    return trianglearea()

elif shape == "circle" or shape == "Circle":
    return circlearea()

elif shape == "square" or shape == "Square":
    return squarearea()

Answer 3

So the actual function should be:  
def shapearea():
shape = raw_input("What shape do you want to print? ")
        if shape == "triangle" or shape == "Triangle":
            return trianglearea()

    elif shape == "circle" or shape == "Circle":
        return circlearea()

    elif shape == "square" or shape == "Square":
        return squarearea()
    else:
        shapearea()

shapearea()

在Python中的条件语句中使用“或”：“if x ==”y“或”z“”

3 个答案: