Question

这在bash中应该是非常直接的，我不知道为什么我在努力。我是一个bash新手，所以请温柔。

伪代码：

    read a configuration file, extract the first line beginning with a key/value pair
    in the format exec=/path/to/myprog -opt1 -opt2 $var1 $var2 ...
    check that the /path/to/myprog is executable
    if executable then
       replace $var1, ... with the contents of the same bash variables in the script
       check that all variables were replaced with existing bash variables
       if aok 
           execute the command and be happy
       else
           complain echoing the partially-substituted command string
       fi
    else
       complain echoing the un-substituted command string
    fi

我尝试的任何东西似乎都没有正常工作。我已经杀了足够的时间尝试各种事情。建议，有人吗？

Answer 1

conf文件：

exec=/bin/ls -l $var1 $var2

bash文件：

#!/bin/bash

CONFIG="tmp.conf"

var1=./
var2=helo

function readconf() {
    args=()
    while IFS=' ' read -ra argv; do
        exec=${argv[0]#*=}
        `command -v ${exec} >/dev/null 2>&1 || { echo >&2 "I require ${exec} but it's not installed.  Aborting."; exit 1; }`
        for i in "${argv[@]:1}"; do
            if [[ $i == \$* ]]; then
                sub=${i:1}
                args+=(${!sub})
            fi
        done
    done < $CONFIG
    echo ${args[@]}
}

readconf

上面的代码提供了实现所需内容所需的关键组件。至少我是这么认为的。您可以根据此骨架添加逻辑。

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1 个答案: