我正在尝试从桌面上的文件夹中运行多个文本文件,我必须从中搜索单词olympic,如果它在50个文本文件中找到olympic,那么应该将它保存在output.txt中,就像 textfile1 = 2 textfile2 = 1,依此类推至texfile = 50
import glob
import re
write_file = open("output.txt")
flist = glob.glob("./*.py") # adjust glob pattern as desired
print flist
print " lines : path to file"
for fpath in flist:
with open(fpath) as f: #open files
lines = f.readlines()
if (lines == 'olympic'):
write_file.write("%s" % lines) #write the results
print "%6d : %s" % (len(lines),fpath)
#with open securely opens and closes the file
write_file.close() # close file
这就是我想要做的,但是我知道它充满了错误:)
我正在尝试运行多个文件,但不是手动运行,我希望它能自动运行整个目录/文件夹的文件并将其输出保存在一个文本文件中。“I have 50 text files and all files have word olympic , some have 1 some have 2/3 etc , i want to count the words from each text file and than save their output in one text file , like textfile1 = 2 , textfile2 = 3 etc in output.txt
答案 0 :(得分:0)
试试这个
import os
import re
filelist = [file for file in os.listdir('.') if '.py' in file]
for file in filelist:
f = open(file,"r")
lines = f.readlines()
sum=0
sum1=0
for line in lines:
if "olympics" in line:
len(re.findall('\Wolympics\W', line))
sum=sum+1
print sum
elif "Olympics" in line:
sum1=sum1+1
print sum1
print "%6d : %s" % (len(line),file.name)
f.close()
不确定你要做什么,但我试了一下......
答案 1 :(得分:0)
类似的东西:
<强> fetch.py 强>
#! /usr/bin/env python
import os
import sys
def get_counts(filepath, niddle):
with open(filepath, 'rb') as f:
return f.read().count(niddle)
if __name__ == '__main__':
folder = sys.argv[1]
niddle = sys.argv[2]
assert os.path.isdir(folder), "Not a folder"
output = open('results.txt', 'w')
for dirpath, dirnames, filenames in os.walk(folder):
for filename in filenames:
if not filename.endswith('.html'): # or whatever
continue
filepath = os.path.abspath('%s/%s' % (dirpath, filename))
result = '%s = %d' % (filepath, get_counts(filepath, niddle))
output.write(result)
output.close()
用作:
$ python fetch.py /path/to/search olimpic