Question

我有以下Visual Basic 2010代码：

Function GetScreenPixel(ByVal Location As Point) As Color
    Dim C As Color
    Using Bmp As New Bitmap(1, 1)
        Using G As Graphics = Graphics.FromImage(Bmp)
            G.CopyFromScreen(Location, Point.Empty, Bmp.Size)
            C = Bmp.GetPixel(0, 0)
        End Using
    End Using
    Return C
End Function

获取屏幕上像素的颜色。

然后我使用类似的东西：

Public Declare Sub mouse_event Lib "user32" Alias "mouse_event" (ByVal dwFlags As Integer, ByVal dx As Integer, ByVal dy As Integer, ByVal cButtons As Integer, ByVal dwExtraInfo As Integer)

Private Sub Timer1_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Timer1.Tick
    If GetScreenPixel(New Point(650, 728)).ToString = "Color [A=255, R=255, G=255, B=255]" Then
        Cursor.Position = New Point(955, 548)
        mouse_event(&H2, 0, 0, 0, 0)
        mouse_event(&H4, 0, 0, 0, 0)
    End If
End Sub

获取屏幕上的某个按钮是否显示并处于活动状态（如果为true，则像素650,728将为白色），如果是，则会单击该按钮。

这很好用。我的问题是，如果我可以以某种方式扩展代码，以便获得像素颜色的函数和单击鼠标的代码都可以应用于非活动窗口。这样我就可以让我的应用程序运行并在必要时单击按钮，我也可以同时使用我的计算机进行其他操作。

我听说过一些叫做的事情：

Public Declare Function FindWindow Lib "user32" Alias "FindWindowA" _
(ByVal lpClassName As String, ByVal lpWindowName As String) As IntPtr

但是我在使用上面显示的示例代码时遇到了很多困难 - 它仍然没有提供在非活动窗口上获取像素颜色的解决方案。

感谢。

Answer 1

为了激活其他窗口，必须在Mouse DOWN和＆amp;之间进行睡眠。向上模拟真实点击

mouse_event(MOUSEEVENTF_LEFTDOWN | MOUSEEVENTF_ABSOLUTE,
     (uint)Convert.ToInt32(position.X * (65535.0 / System.Windows.Forms.Screen.PrimaryScreen.Bounds.Width)),
    (uint)Convert.ToInt32(position.Y * (65535.0 / System.Windows.Forms.Screen.PrimaryScreen.Bounds.Height)), 0, 0);

Thread.Sleep(400);

mouse_event(MOUSEEVENTF_LEFTUP | MOUSEEVENTF_ABSOLUTE,
     (uint)Convert.ToInt32(position.X * (65535.0 / System.Windows.Forms.Screen.PrimaryScreen.Bounds.Width)),
    (uint)Convert.ToInt32(position.Y * (65535.0 / System.Windows.Forms.Screen.PrimaryScreen.Bounds.Height)), 0, 0);

您可能对鼠标移动功能感兴趣 - 应使用MOUSEEVENTF_ABSOLUTE标志设置位置，范围为0 - 65535

mouse_event(MOUSEEVENTF_MOVE | MOUSEEVENTF_ABSOLUTE,
                    (uint)Convert.ToInt32(position.X * (65535.0 / System.Windows.Forms.Screen.PrimaryScreen.Bounds.Width)),
                    (uint)Convert.ToInt32(position.Y * (65535.0 / System.Windows.Forms.Screen.PrimaryScreen.Bounds.Height)), 0, 0);

输入到非活动窗口

1 个答案: