Question

这与我之前关于在按钮点击时移动棒图有关的问题有关新问题是单击同时发送到两个按钮。

左右按钮一切正常。上下拧紧。

HTML

<!DOCTYPE html>
<html>

<style>
    #stage{
        width: 100px;
        height: 100px;
        position: relative;
        border-style: dashed;
        border-color: gray;
        border-width: medium;
    }

    #actor{
        width: 13px;
        height: 15px;
        position: absolute;
        left: 0;
        top: 0;
        background-image: url("E:/Website Projects/man.PNG");

        -webkit-transition: all 2s ease-out 0s;
        -moz-transition: all 2s ease-out 0s;
        transition: all 2s ease-out 0s;
    }


</style>

<body>
    <div id="stage">
        <div id="actor"></div>
    </div>

    <div>
        <button class="control" id="top">TOP</button> <br>
        <button class="control" id="left">LEFT</button> <button class="control" id="right">RIGHT</button> <br>
        <button class="control" id="down">DOWN</button>
    </div>
</body>

<script>
    var vertical = 0;
    var horizontal = 0;
    var shift = 5;

    var top = document.querySelector("#top");
    var left = document.querySelector("#left");
    var right = document.querySelector("#right");
    var down = document.querySelector("#down");

    top.addEventListener("click",moveTop,false);
    left.addEventListener("click",moveLeft,false);
    right.addEventListener("click",moveRight,false);
    down.addEventListener("click",moveDown,false);

    function moveTop(){
        var actor = document.querySelector("#actor");
        if(vertical>0){
            --vertical;
            actor.style.top = shift*vertical + "px";
            console.log("TOP " + "VERTICAL: " + vertical);
        }
    }

    function moveDown(){
        var actor = document.querySelector("#actor");
        if(vertical<17){
            ++vertical;
            actor.style.top = shift*vertical + "px";
            console.log("DOWN " + "VERTICAL: " + vertical);
        }
    }

    function moveRight(){
        var actor = document.querySelector("#actor");
        if(horizontal<17){
            ++horizontal;
            actor.style.left = shift*horizontal + "px";
            console.log("RIGHT " + "HORIZONTAL: " + horizontal);
        }
    }

    function moveLeft(){
        var actor = document.querySelector("#actor");
        if(horizontal>0){
            --horizontal;
            actor.style.left = shift*horizontal + "px";
            console.log("LEFT " + "HORIZONTAL: " + horizontal);
        }
    }

</script>

</html>

控制台日志

DOWN VERTICAL: 1 floating%20man.html:71
TOP VERTICAL: 0 floating%20man.html:62

点击down即可登录。 Top将不起作用，因为它是如何编码的。 Top仅在vertical具有非零值时才有效。

为什么会这样？怎么解决？

Answer 1

标识符top已在Web浏览器中使用，并且引用框架集上的最顶层窗口（如果没有框架，则引用当前窗口）。至少在Chrome上，您无法覆盖它。您必须为按钮引用选择一个新的变量名称。

工作版本：http://jsbin.com/uzanom/1/edit

HTML5单击同时发送到两个按钮

HTML

控制台日志

1 个答案: