Question

请帮助我的代码。我想在我的atm代码中输入一个密码时终止所有字符以及字符和数字的组合。

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>
#include <conio.h>

#define maxx 10

    void menu(),quit(), login();
    void withdrawinq(), depositinq(), balanceinq();

main(void)
{ 
    int userID[ maxx ] = {1010, 1111, 2222, 3333, 4444, 5555, 6666, 7777, 8888, 9999};  
    double balance;
    float deposit, withdraw;
    int pin = 0, x, y, ans;
    char choice;    
    char str[9999];

    for( pin = 1 ;pin <= maxx; pin++ ){

    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  \n\n");
    printf(" ***********************************************************************  \n");
    printf("|                                                                       | \n");    
    printf("*                              MINESKI BANK                             * \n");
    printf("|                                                                       | \n");
    printf(" ***********************************************************************  \n");
    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 LOG IN                            | \n");
    printf(" -----------------------------------------------------------------------  \n");
    printf("|                                                                       | \n");    
    printf("|       Please cover and secure your Account PIN while logging in       | \n");
    printf("|                                                                       | \n");
    printf(" -----------------------------------------------------------------------  \n");         

    printf("\n\n\n Enter PIN Number: ");
    scanf("%d",&pin);
    /* read string */
    fgets(str, sizeof str, stdin);
    /* remove trailing newline from string */
    str[strlen(str) - 1] = '\0';
    /* check string is OK */
    if (strlen(str) != 4 ||
        !isdigit((unsigned char)str[0]) ||
        !isdigit((unsigned char)str[1]) ||
        !isdigit((unsigned char)str[2]) ||
        !isdigit((unsigned char)str[3]))
    {
        printf("Invalid pin, terminating\n");
        system("pause");



    /* convert string to integer */
    pin = atoi(str);    

    printf("\n\n\n"); 

    if(pin == 1010){
    system("cls");
    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  ");   
    printf("\n\n\t\t\t  Name: Carlos Slim Helu");
    printf("\n\t\t\t Account Number: 010030001");
    balance = 7300000;
    printf("\n\n");
    }else if(pin == 1111){

    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  ");   
    printf("\n\n\t\t       Name: William Henry Gates III");
    printf("\n\t\t\t Account Number: 010030002");   
    balance = 6700000;
    printf("\n\n");
    }else if(pin == 2222){

    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  ");   
    printf("\n\n\t\t\t    Name: Amancio Ortega");
    printf("\n\t\t\t Account Number: 010030003");   
    balance = 5700000;
    printf("\n\n");
    }else if(pin == 3333){

    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  ");   
    printf("\n\n\t\t\t   Name: Warren Buffett");
    printf("\n\t\t\tAccount Number: 010030004");    
    balance = 5350000;
    printf("\n\n");
    }else if(pin == 4444){

    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  ");   
    printf("\n\n\t\t\t   Name: Larry Ellison");
    printf("\n\t\t\tAccount Number: 010030005");    
    balance = 4300000;
    printf("\n\n");
    }else if(pin == 5555){

    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  ");   
    printf("\n\n\t\t\t    Name: Charles Koch");
    printf("\n\t\t\tAccount Number: 010030006");    
    balance = 3400000;
    printf("\n\n");
    }else if(pin == 6666){

    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  ");   
    printf("\n\n\t\t\t     Name: David Koch");
    printf("\n\t\t\tAccount Number: 010030007");    
    balance = 3400000;
    printf("\n\n");
    }else if(pin == 7777){

    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  ");
    printf("\n\n\t\t\t    Name: Li Ka-shing");
    printf("\n\t\t\tAccount Number: 010030008");    
    balance = 3100000;
    printf("\n\n");
    }else if(pin == 8888){

    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  ");   
    printf("\n\n\t\t\t Name: Liliane Bettencourt");
    printf("\n\t\t\t Account Number: 010030009");   
    balance = 3000000;
    printf("\n\n");
    }else if(pin == 9999){

    printf("\n -----------------------------------------------------------------------  \n");
    printf("|                                 WELCOME                           | \n");
    printf(" -----------------------------------------------------------------------  ");
    printf("\n\n\t\t\t   Name: Bernard Arnault");
    printf("\n\t\t\t Account Number: 10030000");    
    balance = 2900000;
    printf("\n\n");
    }else{
    printf("\n\n No such account registered.\n\n\n");
    }
    }
    }

这是我的问题！我有10个帐户，您提供的代码先生将不接受代码中的帐户

Answer 1

您应该读取一个字符串，然后检查字符串，然后转换为整数。这样的东西会检查PIN是否正好是四位数。

#include <stdio.h>
#include <stdlib.h>
#include <ctype.h>
#include <string.h>

int main()
{
    char str[99];
    int pin;

    /* read string */
    fgets(str, sizeof str, stdin);
    /* remove trailing newline from string */
    str[strlen(str) - 1] = '\0';
    /* check string is OK */
    if (strlen(str) != 4 ||
        !isdigit((unsigned char)str[0]) ||
        !isdigit((unsigned char)str[1]) ||
        !isdigit((unsigned char)str[2]) ||
        !isdigit((unsigned char)str[3]))
    {
        printf("Invalid pin, terminating\n");
        exit(1);
    }
    /* convert string to integer */
    pin = atoi(str);
}

Answer 2

第一个问题是

printf("\n\n\n Enter PIN Number: ");
scanf("%d",&pin);
/* read string */
fgets(str, sizeof str, stdin);

为什么要尝试两次读取引脚？我向您展示了如何使用fgets阅读它，但您仍在尝试使用scanf阅读它。删除scanf。

第二个问题

if (strlen(str) != 4 ||
        !isdigit((unsigned char)str[0]) ||
        !isdigit((unsigned char)str[1]) ||
        !isdigit((unsigned char)str[2]) ||
        !isdigit((unsigned char)str[3]))
    {
        printf("Invalid pin, terminating\n");
        system("pause");



    /* convert string to integer */
    pin = atoi(str);

您尚未终止if语句，应为

if (strlen(str) != 4 ||
        !isdigit((unsigned char)str[0]) ||
        !isdigit((unsigned char)str[1]) ||
        !isdigit((unsigned char)str[2]) ||
        !isdigit((unsigned char)str[3]))
    {
        printf("Invalid pin, terminating\n");
        system("pause");
    } /*** IF STATEMENT ENDS HERE ***/
else
    {
    /* convert string to integer */
    pin = atoi(str);

等等。您应该尝试自己解决这些问题。它们非常简单，只要让别人为你编写代码就不会学到任何东西。

任何人都可以帮助我的ATM代码吗？

2 个答案: