Question

当我在mysql workbench中运行以下代码时，我得到上面提到的错误请帮忙

#   IF p_Name is not null THEN
 #                   SET m_sql = m_sql +' Name=''' + p_Name + ''' and ';
#   END IF;


     If p_ReligionID is not null THEN
                    SET m_sql = m_sql + '" ReligionId= "' + 'CAST(p_ReligionID AS CHAR(30))' + 'and';
    END IF;

     If p_CasteID is not null THEN
                    SET m_sql = m_sql + '" CasteId= "' + 'CAST(p_CasteID AS CHAR(30))'  + 'and';

    END IF;

    If p_CountryID is not null THEN
                    SET m_sql=m_sql+    '"  Countryid= "' + 'CAST(p_CountryID AS CHAR(30))' + 'and';
    END IF;

    If p_MotherTongueID is not null THEN
                    SET m_sql=m_sql+'"  MotherTongueID= "' + 'CAST(p_MotherTongueID AS CHAR(30))' + 'and';
    END IF;

Answer 1

假设m_sql在输入时有效并且至少有一个条件通过，则最终语句以'和'结束。在我所知的任何方言中，这都不是有效的SQL。然后你必须处理看似无关的引用。

我建议在后续条件的开头插入ANDs

 If p_ReligionID is not null THEN
                SET m_sql = m_sql + ' and ReligionId = ' + 'CAST(p_ReligionID AS CHAR(30))';
END IF;

（我是一个SQL Server人员，因此MySql的程序语言的细节超出了我的范围）

错误代码：1292。截断错误的DOUBLE值：'和'

1 个答案: