我有两个简单的类:CreditCard和Account
#pragma once
#include<string>
class CreditCard
{
private:
std::string number;
int expMonth;
int expYear;
int pin;
public:
CreditCard():number(""), expMonth(0), expYear(0), pin(0)
{
}
CreditCard(std::string number, int expMonth, int expYear,int pin):number(number), expMonth(expMonth), expYear(expYear), pin(pin)
{
if(number.length()!=5)
{
throw std::invalid_argument("Card number must be 5 characters");
}
if(expMonth<0 || expMonth>12)
{
throw std::invalid_argument("Invalid expiration month");
}
if(expYear<2014 || expYear>2020)
{
throw std::invalid_argument("Invalid expiration year");
}
if(pin<1000 || pin>9999)
{
throw std::invalid_argument("PIN must be between 1000 and 9999");
}
}
CreditCard(const CreditCard &creditCard):number(creditCard.number), expMonth(creditCard.expMonth), expYear(creditCard.expYear), pin(creditCard.pin)
{
}
CreditCard(CreditCard &&creditCard):number(std::move(creditCard.number)), expMonth(std::move(creditCard.expMonth)), expYear(std::move(creditCard.expYear)), pin(std::move(creditCard.pin))
{
creditCard.number="";
creditCard.expMonth=0;
creditCard.expYear=0;
creditCard.pin=0;
}
CreditCard& operator = (const CreditCard &creditCard)
{
number=creditCard.number;
expMonth=creditCard.expMonth;
expYear=creditCard.expYear;
pin=creditCard.pin;
return *this;
}
CreditCard& operator = (CreditCard &&creditCard)
{
if(this!=&creditCard)
{
number=std::move(creditCard.number);
expMonth=std::move(creditCard.expMonth);
expYear=std::move(creditCard.expYear);
pin=std::move(creditCard.pin);
number=creditCard.number;
expMonth=creditCard.expMonth;
expYear=creditCard.expYear;
pin=creditCard.pin;
}
return *this;
}
std::string getNumber() const
{
return number;
}
int getExpMonth() const
{
return expMonth;
}
int getExpYear() const
{
return expYear;
}
int getPin() const
{
return pin;
}
};
#pragma once
#include<string>
#include"CreditCard.h"
class Account
{
private:
std::string number;
float amount;
CreditCard creditCard;
public:
Account():number(""), amount(0), creditCard()
{
}
Account(std::string number, float amount, CreditCard creditCard) : number(number), amount(amount), creditCard(creditCard)
{
}
Account(const Account &account) : number(account.number), amount(account.amount), creditCard(account.creditCard)
{
}
Account(Account &&account) : number(std::move(account.number)), amount(std::move(account.amount)), creditCard(std::move(creditCard))
{
}
Account& operator = (const Account &account)
{
number=account.number;
amount=account.amount;
creditCard=account.creditCard;
return *this;
}
Account& operator = (Account &&account)
{
if(this!=&account)
{
number=account.number;
amount=account.amount;
creditCard=account.creditCard;
account.number="";
account.amount=0;
account.creditCard=CreditCard("",0,0,0);
}
return *this;
}
std::string getNumber() const
{
return number;
}
float getAmount() const
{
return amount;
}
void deposit(const float &depositAmount)
{
amount+=depositAmount;
}
void withdraw(const float &withdrawAmount)
{
amount-=withdrawAmount;
}
};
由于我是初学者,我几乎所写的一切都会犯错误。编写移动构造函数的正确方法是什么?我的2移动构造函数/移动赋值运算符应该如何?
答案 0 :(得分:3)
您的构造函数不需要采取任何特殊操作,因此您只需使用构造函数的合成版本:
CreditCard(const CreditCard& creditCard)=default;
CreditCard(CreditCard&& creditCard)=default;
等等。
如果你真的想要实现它们,那么这是一个手工制作的移动复制构造函数的例子。注意构造函数体中没有任何反应。
CreditCard(CreditCard&& creditCard)
:
number(std::move(creditCard.number)),
expMonth(std::move(creditCard.expMonth)),
expYear(std::move(creditCard.expYear)),
pin(std::move(creditCard.pin))
{}
关于副本分配操作员,如果您关心异常安全,可能需要查看copy and swap idiom。
答案 1 :(得分:0)
如果你的班级成员是
std::string number;
int expMonth;
int expYear;
int pin;
并且您将复制构造函数写为:
CreditCard(const CreditCard &creditCard):number(creditCard.number),
expMonth(creditCard.expMonth), expYear(creditCard.expYear),
pin(creditCard.pin){}
那么如果您没有自己指定
,这正是编译器提供的内容你只需要在某些特殊情况下编写复制构造函数,即当你必须动态地分配指针而你不希望指针只是以上面的方式复制'value'时
注意:您没有提供std::string
的初始化,但我不认为这是故意的