Question

我一直在尝试构建一个小应用程序，它从列表框中获取所选项目并将其附加到将要上载的文件的文件名。我可以正确显示所有内容，并且文件上传，但应该附加到文件名的值是'undefined'。这是一个示例：

 function doGet(e) {

 var app = UiApp.createApplication().setTitle("Upload CSV to Sheet");

 var panel = app.createVerticalPanel();
 var listBox = app.createListBox().setName('myList').setId('myList').setWidth('80px');
 listBox.addItem('Value1');
 listBox.addItem('Value2');
 listBox.addItem('Value3');
 listBox.addItem('Value4');

 panel.add(listBox);
 app.add(panel);

   var formContent = app.createVerticalPanel();
   formContent.add(app.createFileUpload().setName('thefile'));
   formContent.add(app.createSubmitButton('Submit'));
   var form = app.createFormPanel();
   form.add(formContent);
   app.add(form);
   return app;
 }

function doPost(e) {
var fileBlob = e.parameter.thefile;
var app = UiApp.getActiveApplication();
   var doc = DocsList.createFile(fileBlob).rename(e.parameter.myList+Utilities.formatDate(new Date(), "GMT", "MM-dd-yy"));
   return app;
 }

如何获取文件名以从listBox获取值？

Answer 1

您已将listBox添加到应用中，而不是将其添加到formpanel内容中。这有两个后果：

1 - 提交后列表仍然可见

2 - doPost未收到该列表，因为它不在表单中......

试试这样：

function doGet() {

 var app = UiApp.createApplication().setTitle("Upload CSV to Sheet");

 var panel = app.createVerticalPanel();
 var listBox = app.createListBox().setName('myList').setId('myList').setWidth('80px');
 listBox.addItem('Value1');
 listBox.addItem('Value2');
 listBox.addItem('Value3');
 listBox.addItem('Value4');

 panel.add(listBox);

   var formContent = app.createVerticalPanel();
   formContent.add(app.createFileUpload().setName('thefile'));
   formContent.add(app.createSubmitButton('Submit'));
   formContent.add(panel);
   var form = app.createFormPanel();
   form.add(formContent);
   app.add(form);
   return app;
 }

function doPost(e) {
  var fileBlob = e.parameter.thefile;
  var doc = DocsList.createFile(fileBlob).rename(e.parameter.myList+' '+Utilities.formatDate(new Date(), "GMT", "MM-dd-yy"));
  var app = UiApp.getActiveApplication();
  return app;
 }

如何将选定的listBox项目作为字符串？

1 个答案: