好吧,看起来我的主要课遇到了一些问题。它在第二次运行时打破了我的循环并显示和错误。它说我的扫描仪从菜单中读取用户选择是否产生错误?怎么样,它在第一个循环中运行,但由于某种原因它不能再运行。
"action = new Scanner(System.in).nextInt();"
正在生成错误。有谁知道为什么会发生这种情况,因为当用户选择菜单选项时,读取用户输入的整数非常重要。
import java.util.Scanner;
import java.io.FileWriter;
import java.io.IOException;
import java.io.PrintWriter;
import java.lang.String;
import java.lang.System;
public class MainActions {
public static void main(String args[]) throws IOException {
int action = 0;
while (action != 6) {
Contact.menu();
new Scanner(System.in);
action = new Scanner(System.in).nextInt();
if (action <= 0 || action > 6) {
System.out.println("Invalid selection. ");
}
switch (action) {
case 1:
MainActions.addContactInfo();
break;
case 2:
break;
case 3:
break;
case 4:
break;
case 5:
break;
}
}
}
public static void addContactInfo() {
Contact contact;
contact = new Contact();
Scanner reader = new Scanner(System.in);
System.out.println("Enter Contact Last Name:");
String lastname = reader.nextLine();
contact.setLastName(lastname);
System.out.println("Enter Contact First Name: ");
contact.setFirstName(reader.nextLine());
System.out.println("Enter Contact Street Address: ");
contact.setHouseAddress(reader.nextLine());
System.out.println("Enter Contact City: ");
contact.setCity(reader.nextLine());
System.out.println("Enter Contact Zip Code: ");
contact.setZip(reader.nextLine());
System.out.println("Enter Contact Email: ");
contact.setEmail(reader.nextLine());
System.out.println("Enter Contact Phone Number: ");
contact.setPhone(reader.nextLine());
System.out.println("Enter Contact Notes: ");
contact.setNotes(reader.nextLine());
if (lastname.trim().equals("")) {
System.out.println("\nLast name was blank, contact not saved.");
System.exit(0);
} else {
ContactList list;
list = new ContactList();
list.add(contact);
list.save();
Contact c = contact;
try (PrintWriter output = new PrintWriter(new FileWriter("contactlist.csv", true))) {
output.printf("%s\r\n", c);
} catch (Exception e) {}
}
reader.close();
}
}
控制台:
1. Enter a new person
2. Print the contact list
3. Retrieve a person's information by last name
4. Retrieve a person's information by email address
5. Retrieve all people who live in a given zip code
6. Exit
1
Enter Contact Last Name:
asdf
Enter Contact First Name:
asdf
Enter Contact Street Address:
asdf
Enter Contact City:
asdf
Enter Contact Zip Code:
asdf
Enter Contact Email:
asdf
Enter Contact Phone Number:
asdf
Enter Contact Notes:
asdf
Contact information has been saved.
Exception in thread "main" java.util.NoSuchElementException
at java.util.Scanner.throwFor(Unknown Source)
at java.util.Scanner.next(Unknown Source)
at java.util.Scanner.nextInt(Unknown Source)
at java.util.Scanner.nextInt(Unknown Source)
at MainActions.main(MainActions.java:33)
1. Enter a new person
2. Print the contact list
3. Retrieve a person's information by last name
4. Retrieve a person's information by email address
5. Retrieve all people who live in a given zip code
6. Exit
答案 0 :(得分:2)
替换
new Scanner(System.in);
action = new Scanner(System.in).nextInt();
使用
Scanner scan = new Scanner(System.in);
action = scan.nextInt();
答案 1 :(得分:1)
new Scanner(System.in); // Remove this. Not needed.
action = new Scanner(System.in).nextInt();
等等,这不是问题。这是实际问题。
reader.close();
addContactInfo()
中的这一行是罪魁祸首。删除它,您的代码将起作用。
此reader.close()
会关闭您方法中的Scanner
(扫描System.in
),因为两者都在扫描System.in
。
希望这能解决您的问题。我碰巧找到了this question on SO。请查看此内容以获取更详细的说明。
文档说: -
public void close()抛出IOException
关闭此输入流并释放所有关联的系统资源 用这个流。普遍的合约是它关闭了 输入流。封闭流不能执行输入操作 不能重新开放。