当应用程序在前台运行时,在警告框中显示推送通知

时间:2013-03-22 15:25:15

标签: android push-notification google-cloud-messaging

我在我的Android应用程序中执行由GCM触发的推送通知。我想显示通知,如果应用程序在警告框中运行,如果应用程序未运行意味着不在前台只显示状态栏通知,您如何确定应用程序是否正在运行并且在前台?是这可以显示这样的通知。现在使用此代码显示状态栏推送通知

  NotificationManager notificationManager = (NotificationManager)
                context.getSystemService(Context.NOTIFICATION_SERVICE);
        Notification notification = new Notification(icon, message, when);

        String title = context.getString(R.string.app_name);

         Intent notificationIntent = new Intent(context, BottomActivity.class);
        // set intent so it does not start a new activity
        notificationIntent.setFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_SINGLE_TOP);
        PendingIntent intent = PendingIntent.getActivity(context, 0, notificationIntent, 0);
        notification.setLatestEventInfo(context, title, message, intent);
        notification.flags |= Notification.FLAG_AUTO_CANCEL;

        // Play default notification sound
        notification.defaults |= Notification.DEFAULT_SOUND;

        //notification.sound = Uri.parse("android.resource://" + context.getPackageName() + "your_sound_file_name.mp3");

        // Vibrate if vibrate is enabled
        notification.defaults |= Notification.DEFAULT_VIBRATE;
        notificationManager.notify(0, notification); 

3 个答案:

答案 0 :(得分:2)

您可以像对话一样创建新的活动和主题,并检查前台活动。检查以下代码。

         ActivityManager activityManager = (ActivityManager) context.getSystemService(Context.ACTIVITY_SERVICE);
        List<RunningTaskInfo> services = activityManager
                .getRunningTasks(Integer.MAX_VALUE);
        boolean isActivityFound = false;

        if (services.get(0).topActivity.getPackageName().toString()
                .equalsIgnoreCase(context.getPackageName().toString())) {
            isActivityFound = true;
        }

       if (isActivityFound) {
            resultIntent = new Intent(context, AlertDialogNotification.class);
            resultIntent.putExtra(EXTRA_ALERT_MESSAGE_BEAUTIFUL, "anyMessage");
            resultIntent.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
            context.startActivity(resultIntent); 
        }

在清单中将主题设为活动的对话框。希望能帮助到你。如果您有问题,请告诉我们。

答案 1 :(得分:1)

你有多少活动?如果只有一个,那么在onResume()和onPause()(AKA处于活动状态)之间保持单例引用是很容易的,如果是,则从接收器调用活动。如果你有很多活动,你可以通过为它们提供一个共同的基类来实现类似的逻辑。像这样:

class MyActivity: Activity
{
    static private MyActivity _Current = null;

    protected void onResume() //Activated
    {
        super.onResume();
        _Current = this;
    }

    protected void onPause() //Deactivated
    {
        super.onPause();
        _Current = null;
    }

    //This is for the receiver to call
    static public PopAlert()
    {
        if(_Current != null)
        {
            new AlertDialog.Builder(_Current)
                .setMessage("Hello world")
                //More alert setup; use _Current as a context object
                .create().show();
        }
    } 
}

答案 2 :(得分:0)

请尝试这些

public static boolean isAppIsInBackground(Context context) {

        boolean isInBackground = true;
        ActivityManager am = (ActivityManager)context.getSystemService(Context.ACTIVITY_SERVICE);
        if (Build.VERSION.SDK_INT > Build.VERSION_CODES.KITKAT_WATCH) {
            List<ActivityManager.RunningAppProcessInfo> runningProcesses = am.getRunningAppProcesses();
            for (ActivityManager.RunningAppProcessInfo processInfo : runningProcesses) {
                if (processInfo.importance == ActivityManager.RunningAppProcessInfo.IMPORTANCE_FOREGROUND) {
                    for (String activeProcess : processInfo.pkgList) {
                        if (activeProcess.equals(context.getPackageName()))
                            isInBackground = false;
                    }
                }
            }
        } else {
            List<ActivityManager.RunningTaskInfo> taskInfo = am.getRunningTasks(1);
            ComponentName componentInfo = taskInfo.get(0).topActivity;
            if (componentInfo.getPackageName().equals(context.getPackageName())) {
                isInBackground = false;
            }
        }