编辑:我认为最终输出看起来不像JSON。如果没有,那是什么?
我有这段代码:
$url = 'http://eligibility.sc.egov.usda.gov/eligibility/eligibilityservice?eligibilityType=Property&requestString=<?xml version="1.0"?><Eligibility xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:noNamespaceSchemaLocation="/var/lib/tomcat5/webapps/eligibility/Eligibilitywsdl.xsd"><PropertyRequest StreetAddress1="'.$street.'" StreetAddress2="" StreetAddress3="" City="'.$city.'" State="'.$state.'" County="" Zip="'.$zip.'" Program="RBS"></PropertyRequest></Eligibility>';
$url_arr = explode( 'requestString=', $url );
$xml = simplexml_load_string( $url_arr[ 1 ] ); // requires allow_url_fopen to be on
$elg = (string)$xml->Property[Eligibility];
var_dump($xml);
$xml = simplexml_load_file($url); // requires allow_url_fopen to be on
$elg = json_encode((string)$xml->Property[Eligibility]);
var_dump($elg);
将这个阵列放在哪个位置:
object(SimpleXMLElement)#1 (1) {
["PropertyRequest"]=> object(SimpleXMLElement)#2 (1) {
["@attributes"]=> array(8) {
["StreetAddress1"]=> string(13) "7865 ILLINOIS"
["StreetAddress2"]=> string(0) ""
["StreetAddress3"]=> string(0) ""
["City"]=> string(10) "CASEYVILLE"
["State"]=> string(2) "IL"
["County"]=> string(0) ""
["Zip"]=> string(5) "62232"
["Program"]=> string(3) "RBS"
}
}
}
string(12) ""InEligible""
我只想抓住string(12) ""InEligible""
部分。我怎么把它变成一个变量?
答案 0 :(得分:1)
从您的代码中$elg
已经拥有此值,它是一个变量。
答案 1 :(得分:0)
编辑:我认为最终输出看起来不像JSON。如果没有,那是什么?
string(12) ""InEligible""
那是JSON。 JSON中的字符串用引号括起来,不多也不少。