Question

我有一个查询将显示所有选定的记录，除了MAX记录（每个查询最多可以有5条记录）。但是，它会在不同的行上显示它。如何在一行中显示结果？

当前数据：

John Smith 
Jack Smith
Gerald Smith

一行中的所需数据（或在单独的字段中但不是多行）：

约翰史密斯;杰克史密斯;杰拉尔德史密斯

SQL语句：

 SELECT distinct /*all existing records */
 rtrim(ltrim(pn.sFirstName + ' ' + pn.uLastName)) as record1,
 '' as record2,
 ''  as record3,
 '' as record4,
 '' as record5
 FROM tenant t (nolock)
 INNER JOIN person pn (nolock) on pn.hmy = t.person
 WHERE pn.hmy <>
 (SELECT MAX(pn.hmy) 
 FROM tenant t (nolock)
 INNER JOIN person pn (nolock) on pn.hmy = t.person
 WHERE t.scode = '111111'
 )and t.scode = '111111'

感谢您的帮助！

Answer 1

看起来您正在使用SQL Server。如果您使用的是2005或更高版本，则可以使用row_number()：

执行此操作

SELECT (case when seqnum = 2 then rtrim(ltrim(max(pn.sFirstName+ ' ' + pn.uLastName)))  as record1,
       (case when seqnum = 3 then rtrim(ltrim(max(pn.sFirstName+ ' ' + pn.uLastName)))  as record2,
       (case when seqnum = 4 then rtrim(ltrim(max(pn.sFirstName+ ' ' + pn.uLastName)))  as record3,
       (case when seqnum = 5 then rtrim(ltrim(max(pn.sFirstName+ ' ' + pn.uLastName)))  as record4,
       (case when seqnum = 6 then rtrim(ltrim(max(pn.sFirstName+ ' ' + pn.uLastName)))  as record5
 FROM (select pn.*,
              ROW_NUMBER() over (partition by t.scode order by pn.hmy desc) as seqnum
       from tenant t (nolock) INNER JOIN
            person pn (nolock)
            on pn.hmy = t.person
       where t.scode = '111111'
      ) pn

内部查询根据pn.hmy分配序号，最大值为1.外部查询汇总数据，使用条件选择第二到第六个值。

Answer 2

您需要一个变量来保存该信息，例如

declare @result;
set @result = '';

select @result = @result + ',' + rtrim(ltrim(pn.sFirstName + ' ' + pn.uLastName))  
from ..... 

select substring(@result, 0, len(@result));

在SQL中的一行上显示多条记录

2 个答案: