Question

select top 2  
    CONVERT(varchar(6),a.lastdate,6) as lastdate
    ,(select name from table_states where ID=a.joblocation ) as locat
    ,* 
from table_jobpost as a 
inner join (select * 
            from table_SuperAdmin as b 
            inner join table_Renewal as c on b.S_id=c.supid 
            where **c.proid** in (select [plan] 
                                    from table_features 
                                    where Fjobs=1) 
            and c.Payed=1) as aa on a.oid=aa.businessid 
where a.status=1 
and a.lastdate>GETDATE() 
order by startdate desc

在上面的查询c.proid中我想要：

select top 1 proid from table_Renewal  order by renewalid desc

如何重新排列查询？

现在在c.proid我有多个id.so它将检查所有ID。我想只检查

select top 1 proid from table_Renewal  order by renewalid desc

Answer 1

不确定我是否正确理解了您的问题。但请参阅下面的答案

从table_Renewal

中选择max（proid）你可以试试吗

选择前2名 CONVERT（varchar（6），a.lastdate，6）作为lastdate ，（从table_states中选择ID = a.joblocation的名称）作为locat * 来自table_jobpost作为内连接（选择* 从table_SuperAdmin作为b 内部联接table_Renewal as b on b.S_id = c.supid 左外连接（选择max（proid）as proid1，supid from table_Renewal group by supid）as c1 on b.S_id = c1.supid 其中c1.proid1 （选择[计划] 来自table_features 其中Fjobs = 1）和c.Payed = 1）aa on a.oid = aa.businessid 其中a.status = 1 和a.lastdate＆gt; GETDATE（）按startdate desc命令

如何在加入时为列编写查询

1 个答案: