Question

在这个帖子上我有一个问题已成功回答。

searching for filtered duplicates in access query

现在我有第二个问题。也许有人可以帮助我。

我的查询如下：

查询A_Gravur：

SP1 | SP2     | SP3

 64 | CB75000 | 3
 64 | empty   | D
 70 | CB70010 | 1
 70 | CB70010 | 1
119 | CB70050 | 5
119 | empty   | D
165 | S15002  | Schalter
165 | S15002  | Schalter
194 | R70034  | Poti
194 | R10023  | Potentiometer
196 | S10063  | Schalter
196 | S10063  | Schalter
197 | S10063  | Schalter
198 | S10070  | 3
199 | CB75000 | 5

此查询由另一个查询过滤以检查重复项。最终结果如下：

结果：

SP1 | SP2     | SP3

194 | R70034  | Poti 470k
194 | R10023  | Potentiometer
196 | S10063  | Schalter
197 | S10063  | Schalter
 64 | CB75000 | 3
199 | CB75000 | 5

，SQL代码如下所示：

  SELECT SP1, SP2, SP3
  FROM A_Gravur
  WHERE (SP1 IN
    (SELECT SP1
      FROM A_Gravur
      WHERE SP3<>'D'
      GROUP BY SP1
      HAVING COUNT(*)>1)
  OR SP2 IN
    (SELECT SP2
      FROM A_Gravur
      WHERE SP3<>'D'
      GROUP BY SP2
      HAVING COUNT(*)>1))
  AND CONCAT(CAST(SP1 AS CHAR),SP2,SP3) NOT IN
    (SELECT CONCAT(CAST(SP1 AS CHAR),SP2,SP3)
      FROM A_Gravur
      WHERE SP3 <> 'D'
      GROUP BY CONCAT(CAST(SP1 AS CHAR),SP2,SP3)
      HAVING COUNT(*)>1)
  AND SP3<>'D'
  ORDER BY SP1, SP2;

现在我的新问题：

我在查询A_Gravur（SP4和SP5）中添加了2个新列并进行了重复搜索

SP1 | SP2     | SP3           | SP4     | SP5       |

194 | R70034  | Poti 470k     |123546   |88859     
194 | R10023  | Potentiometer |88859    |
196 | S10063  | Schalter      |7773     |
197 | S10063  | Schalter      |99992    |
 64 | CB75000 | 3             |177777   |
199 | CB75000 | 5             |99999    |

解释：在SP4中总有值（Materialnumber）。现在，当我搜索重复项时，它应该只找到这个结果：

SP1 | SP2     | SP3           | SP4     | SP5       |

196 | S10063  | Schalter      |7773     |
197 | S10063  | Schalter      |99992    |
 64 | CB75000 | 3             |177777   |
199 | CB75000 | 5             |99999    |

因为SP5中的数字（88859）也在SP4（88859）中，并且SP1在两个记录中都是相同的数字（194）

但如果看起来像这样，那么结果是正确的

SP1 | SP2     | SP3           | SP4     | SP5       |

194 | R70034  | Poti 470k     |123546   |0000001     
194 | R10023  | Potentiometer |88859    |
196 | S10063  | Schalter      |7773     |
197 | S10063  | Schalter      |99992    |
 64 | CB75000 | 3             |177777   |
199 | CB75000 | 5             |99999    |

感谢您的帮助!!

Answer 1

这可能会做你想要的：

SELECT SP1, SP2, SP3, SP4, SP5
FROM A_Gravur
WHERE (SP1 IN
  (SELECT SP1
    FROM A_Gravur
    WHERE SP3<>'D'
    GROUP BY SP1
    HAVING COUNT(*)>1)
OR SP2 IN
  (SELECT SP2
    FROM A_Gravur
    WHERE SP3<>'D'
    GROUP BY SP2
    HAVING COUNT(*)>1))
AND CONCAT(CAST(SP1 AS CHAR), SP2,
    CAST(COALESCE(SP5, SP4) AS CHAR)) NOT IN
  (SELECT CONCAT(CAST(SP1 AS CHAR), SP2,
    CAST(COALESCE(SP5, SP4) AS CHAR))
    FROM A_Gravur
    WHERE SP3 <> 'D'
    GROUP BY CONCAT(CAST(SP1 AS CHAR),SP2,
      CAST(COALESCE(SP5, SP4) AS CHAR))
    HAVING COUNT(*)>1)
AND SP3<>'D'
ORDER BY SP1, SP2, SP3, SP4;

CONCAT()选择第一个非空的字段，因此如果存在则选择SP5，否则选择SP4。

这是SQL Fiddle。如果我没有正确理解，请你修改那里的测试数据，并添加一个注释与新的SQL Fiddle的地址，以便我有好的数据可供使用。

SQL筛选由查询中的不同列复制

1 个答案: