PHP插入中的mysqli_affected_rows

Question

我有这段代码：

if(mail($to, $subject, $message, $headers)){
    $insert_member_sql = "INSERT INTO members (id, username) VALUES('$id', '$username')";
    $insert_member_res = mysqli_query($con, $insert_member_sql);
    if(mysqli_affected_rows($con, $insert_member_res)>0){
    echo "1";
    }else{
    echo "0";
    }
};

一切正常，发送电子邮件并将信息插入数据库但mysqli_affected_rows不起作用 - 如何在运行查询后编辑此代码以回显1？

Answer 1

更改此

if(mysqli_affected_rows($con, $insert_member_res)>0)

到

if(mysqli_affected_rows($con)>0)

mysqli_affected_rows只需要connection link个对象，但您也传递了查询对象也是问题

Answer 2

或者你可以回应它

echo mysqli_affected_rows($con);

如果您想要仔细检查课程

Answer 3

if(mail($to, $subject, $message, $headers)){
    $insert_member_sql = "INSERT INTO members (id, username) VALUES('$id', '$username')";

    if (!mysql_query($insert_member_sql) ){
    echo "1";
    }else{
    echo "0";
    }
};