Question

我从支付网关（JSON）获得以下响应：

    {
  "response": {
    "token": "ch_lfUYEBK14zotCTykezJkfg",
    "success": true,
    "amount": 400,
    "currency": null,
    "description": "test charge",
    "email": "user@user.com",
    "ip_address": "203.192.1.172",
    "created_at": "2012-06-20T03:10:49Z",
    "status_message": "Success!",
    "error_message": null,
    "card": {
      "token": "card_nytGw7koRg23EEp9NTmz9w",
      "display_number": "XXXX-XXXX-XXXX-0000",
      "scheme": "master",
      "address_line1": "42 Sevenoaks St",
      "address_line2": null,
      "address_city": "Lathlain",
      "address_postcode": "6454",
      "address_state": "WA",
      "address_country": "Australia"
    },
    "transfer": null
  }
}

我正试图将success => true部分放在if语句中，如下所示：

<?php
    if($response['success'] == true) {
     // continue transaction
    }
?>

没有任何运气，所以我要求我如何实现这一目标。能够提取其他键值也很有用。

谢谢

Answer 1

<强>更新

您的$response已经是一个对象，因此该表达式应该有效：

if ($response->response->success == true) {
    // etc
}

您是否只是在寻找解码字符串表示的代码？如果是这样的话：

$response = <<<'EOM'
{
  "response": {
    "token": "ch_lfUYEBK14zotCTykezJkfg",
    "success": true,
    "amount": 400,
    "currency": null,
    "description": "test charge",
    "email": "user@user.com",
    "ip_address": "203.192.1.172",
    "created_at": "2012-06-20T03:10:49Z",
    "status_message": "Success!",
    "error_message": null,
    "card": {
      "token": "card_nytGw7koRg23EEp9NTmz9w",
      "display_number": "XXXX-XXXX-XXXX-0000",
      "scheme": "master",
      "address_line1": "42 Sevenoaks St",
      "address_line2": null,
      "address_city": "Lathlain",
      "address_postcode": "6454",
      "address_state": "WA",
      "address_country": "Australia"
    },
    "transfer": null
  }
}
EOM;

$responseData = json_decode($responseText, true);

if ($responseData['response']['success'] == true) {
 // continue transaction
}

Answer 2

您无法json_decode($response)的原因是因为$response是一个对象，而不是一个JSON字符串。

根据https://github.com/noetix/pin-php/blob/master/src/Pin/Handler.php#L87

，Pin-PHP库会自动为您解码所有请求

要查看响应是否成功，请使用响应对象作为对象：

if ($response->response->success) {
    echo "Success!";
} else {
    echo "Failed :(";
}

Answer 3

为什么不直接使用json对象：

$jsonobject = json_encode($responseText);
$response = $jsonobject->response->success;
if($response === true) {
    // code here
}

在PHP中从JSON数组中提取特定键值

3 个答案: