Question

我有点坚持这个问题。我试图在一个字符串中存储1个或多个单词，找到所有单词组合的长度，然后除以单词数来找到平均值。我需要在while循环中执行此操作（这是作业的目标）

当我输入“Hello my name is”时，它返回长度为

Result:  
5  
2  
4  
2

但我想要的是添加这些结果然后除以单词数量

5+2+4+2 = 13  
13/4 = 3.25

这是我到目前为止所做的：

Scanner in = new Scanner(System.in);

int counter = 0;
double sum = 0;

while (in.hasNext()) {
    String word = in.next();
    double totalchar = word.length();
    sum = totalchar + sum;
    counter++;


    double average = 0;
    if (counter > 0) {
        average = sum / counter;

    }
    System.out.println(average);
}

Answer 1

只需移动average计算并在while循环外打印：

while (in.hasNext()) {
    String word = in.next();
    if (word.equals("exit")) {
        break;
    }
    double totalchar = word.length();
    sum = totalchar + sum;
    counter++;
}
double average = 0;
if (counter > 0) {
    average = sum / counter;
}
System.out.println(average);

Answer 2

也许这有助于你：
您必须将计算从average 移出 while循环
或者每次都会计算和打印！

我也改进了一点。（你不需要每次都加倍）

Scanner scanner = new Scanner(System.in);

int sum = 0;
int counter = 0;

while (in.hasNext())
{
    sum += in.next().length();
    counter++;
}

double average = 0.0;
if (counter > 0)
    average = sum / counter;

System.out.println(average);

Answer 3

请参阅下面的增强版本：

    int counter = 0;
    int sum = 0; // not yet needed to be of type double
    String word = null;

    while (in.hasNext()) {
        word = in.next();
        sum += word.length();
        counter++;
    }

    double average = 0;
    if (counter > 0) {
        average = sum / counter;
    }
    System.out.println(average);

请在循环中重新分配变量在之外。>
将你的计数器检查在循环中是不好的，因为你将反复创建平均值，并检查计数器是否为0。这样，它会缩短处理周转时间。

Answer 4

以下示例使用BufferedReader：

import java.util.*;
import java.io.*;
class WordAmount {
public static void main(String... args) throws IOException{
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String line = "";

while((line=br.readLine())!=null) {
   if(line.length() > 0) {
   String[] words = line.split(" ");
   int totalWords = words.length;
   int totalChars = 0;
   System.out.println("Number of words: "+totalWords);
   for(int i=0;i<words.length;i++) {
      System.out.println("Length 0f "+words[i]+" : "+words[i].length());
      totalChars += words[i].length();
   }
   System.out.println("Average count :"+ ((double)totalChars/totalWords));
  }
}
}
}

在单个字符串中查找每个字的平均字符数

4 个答案: