Question

我有一个嵌套列表，可以显示客户及其电话号码：

杰森

555 111-1111
555 222-2222

克里斯汀

555 333-3333

约翰

555 444-4444
555 555-5555
555 656-6666

但是，我在添加电子邮件时遇到了麻烦。此代码只是复制每个电话号码下的电子邮件，但我需要将电话号码和电子邮件分组到每个客户下面，如：

杰森

555 111-1111
555 222-2222
jason@jason.com
jason.alternative@jason.com

克里斯汀

555 333-3333
kristen@kristen.com
kristen.alternative@kristen.com
kristen.personal@kristen.com

约翰

555 444-4444
555 555-5555
555 656-6666
john@john.com

PHP代码：

<?php
$result = mysqli_query($dbc,"
SELECT 
fname, 
phone, 
email
FROM 
customer, 
phone, 
email, 
customer_phone, 
customer_email
WHERE
customer.id=customer_phone.customer_id
AND
phone.id=customer_phone.phone_id
AND
customer.id=customer_email.customer_id
AND
email.id=customer_email.email_id
order by fname
");

$oldname = null;
while($row = mysqli_fetch_array($result))
{
    if($oldname != $row['fname'])
    {
        echo "<h3>".$row['fname']."</h3>";
        $oldname = $row['fname'];
    }
    echo "<p>".$row['phone']."</p>";
    echo "<p>".$row['email']."</p>";
}
?>

Answer 1

此查询将在电话号码后插入电子邮件，首先获取电话号码，然后输入电子邮件。带有“1-Phone”和“2-Email”的列可确保电子邮件在电话号码后排序。

SELECT fname, '1-Phone' AS InfoType, phone AS TheInfo
  FROM Customer
  INNER JOIN phone ON phone.id=customer_phone.phone_id
  INNER JOIN customer_phone ON customer.id=customer_phone.customer_id
UNION SELECT fname, '2-Email', email
  FROM Customer
  INNER JOIN email ON email.id=customer_email.email_id
  INNER JOIN customer_email ON customer.id=customer_email.customer_id
ORDER BY fname, InfoType

我将连接更改为ANSI语法，因为它使我更容易处理这个问题;没有其他原因。如果这是您的偏好，请随意将连接条件推回到WHERE子句 - 我对此不感到强烈：）

渲染代码的唯一变化是替换它......

echo "<p>".$row['phone']."</p>";
echo "<p>".$row['email']."</p>";

......用这个：

echo "<p>".$row['TheInfo']."</p>";

PHP MySQL嵌套客户数据列表

1 个答案: