我为IQueryable创建了一个通用搜索扩展方法,使您可以搜索单个属性以查看其中是否包含搜索词。
http://jnye.co/Posts/6/c%23-generic-search-extension-method-for-iqueryable
我现在想要让用户选择要在每个属性中搜索的多个属性,如果 任何 属性包含文本,则匹配。
代码:
用户输入以下代码以执行此搜索:
string searchTerm = "Essex";
context.Clubs.Search(searchTerm, club => club.Name, club => club.County)
//Note: If possible I would rather something closer to the following syntax...
context.Clubs.Search(club => new[]{ club.Name, club.County}, searchTerm);
// ... or, even better, something similar to this...
context.Clubs.Search(club => new { club.Name, club.County}, searchTerm);
这将返回任何名称为“Essex”的高尔夫球杆或县。
public static IQueryable<TSource> Search<TSource>(this IQueryable<TSource> source, string searchTerm, params Expression<Func<TSource, string>>[] stringProperties)
{
if (String.IsNullOrEmpty(searchTerm))
{
return source;
}
// The lamda I would like to reproduce:
// source.Where(x => x.[property1].Contains(searchTerm)
// || x.[property2].Contains(searchTerm)
// || x.[property3].Contains(searchTerm)...)
//Create expression to represent x.[property1].Contains(searchTerm)
var searchTermExpression = Expression.Constant(searchTerm);
//Build parameters
var parameters = stringProperties.SelectMany(prop => prop.Parameters);
Expression orExpression = null;
//Build a contains expression for each property
foreach (var stringProperty in stringProperties)
{
var checkContainsExpression = Expression.Call(stringProperty.Body, typeof(string).GetMethod("Contains"), searchTermExpression);
if (orExpression == null)
{
orExpression = checkContainsExpression;
}
//Build or expression for each property
orExpression = Expression.OrElse(orExpression, checkContainsExpression);
}
var methodCallExpression = Expression.Call(typeof(Queryable),
"Where",
new Type[] { source.ElementType },
source.Expression,
Expression.Lambda<Func<TSource, bool>>(orExpression, parameters));
return source.Provider.CreateQuery<TSource>(methodCallExpression);
}
错误
如果我将提供的参数数量更改为1:
Expression.Lambda<Func<TSource, bool>>(orExpression, parameters.First()));
我收到一个新错误:
更新
我写过a post on the work discussed in this question。 Check it out on GitHub也是。
答案 0 :(得分:3)
我们走了;你非常接近 - 正如我在评论中所指出的,这里的关键部分是使用ExpressionVisitor
根据你想要保留的单个参数重新编写树:
using System;
using System.Linq;
using System.Linq.Expressions;
static class Program
{
static void Main()
{
var data = new[] { new Foo { A = "x1", B = "y1", C = "y1" }, new Foo { A = "y2", B = "y2", C = "y2" },
new Foo { A = "y3", B = "y3", C = "x3" } }.AsQueryable();
var result = data.Search("x", x => x.A, x => x.B, x => x.C);
foreach (var row in result)
{
Console.WriteLine("{0}, {1}, {2}", row.A, row.B, row.C);
}
}
class Foo
{
public string A { get; set; }
public string B { get; set; }
public string C { get; set; }
}
public class SwapVisitor : ExpressionVisitor
{
private readonly Expression from, to;
public SwapVisitor(Expression from, Expression to)
{
this.from = from;
this.to = to;
}
public override Expression Visit(Expression node)
{
return node == from ? to : base.Visit(node);
}
public static Expression Swap(Expression body, Expression from, Expression to)
{
return new SwapVisitor(from, to).Visit(body);
}
}
public static IQueryable<TSource> Search<TSource>(this IQueryable<TSource> source, string searchTerm, params Expression<Func<TSource, string>>[] stringProperties)
{
if (String.IsNullOrEmpty(searchTerm))
{
return source;
}
if (stringProperties.Length == 0) return source.Where(x => false);
// The lamda I would like to reproduce:
// source.Where(x => x.[property1].Contains(searchTerm)
// || x.[property2].Contains(searchTerm)
// || x.[property3].Contains(searchTerm)...)
//Create expression to represent x.[property1].Contains(searchTerm)
var searchTermExpression = Expression.Constant(searchTerm);
var param = stringProperties[0].Parameters.Single();
Expression orExpression = null;
//Build a contains expression for each property
foreach (var stringProperty in stringProperties)
{
// re-write the property using the param we want to keep
var body = SwapVisitor.Swap(stringProperty.Body, stringProperty.Parameters.Single(), param);
var checkContainsExpression = Expression.Call(
body, typeof(string).GetMethod("Contains"), searchTermExpression);
if (orExpression == null)
{
orExpression = checkContainsExpression;
}
else
{ // compose
orExpression = Expression.OrElse(orExpression, checkContainsExpression);
}
}
var lambda = Expression.Lambda<Func<TSource, bool>>(orExpression, param);
return source.Where(lambda);
}
}