public static void sample(BufferedImage image) {
int width = image.getWidth();
int height = image.getHeight();
int value[][] = new int[width][height];
int valueR[][] = new int[width][height];
int valueG[][] = new int[width][height];
int valueB[][] = new int[width][height];
for (int j = 0; j < height; j++) {
for (int i = 0; i < width; i++) {
int pixel = image.getRGB(i, j);
value[i][j] = pixel;
Color c = new Color(pixel);
valueR[i][j]= c.getRed();
valueG[i][j] = c.getGreen();
valueB[i][j] = c.getBlue();
System.out.println("Red value = "+valueR[i][j]);
System.out.println("Green value ="+valueG[i][j]);
System.out.println("Blue value"+valueB[i][j]);
}
}
}
上面的代码是分别在一个数组中存储图像的RGB值和像素颜色值。
public static BigInteger modPow(BigInteger a1, BigInteger e, BigInteger n) {
BigInteger r = 1;
for (int i = e.bitLength() - 1; i >= 0; i--) {
r = (r.multiply(r)).mod(n);
if (e.testBit(i)) {
r = (r.multiply(a1)).mod(n);
}
}
System.out.println("C value = " + r);
int lng = 3;
BigInteger bi = BigInteger.valueOf(lng);
BigInteger a = r.divide(bi);
BigInteger b = r.mod(bi);
System.out.println("pixel position a = " + a);
System.out.println("modulus value b = " + b);
return r;
}
在上面的代码中找到我需要嵌入秘密位的像素位置。所以我需要去那个特定的像素来嵌入消息。但是在前面的代码中我将像素颜色存储在数组值[] []中.i需要搜索数组值[] []以获取我在上一个代码中得到的像素位置。
注意: a1是要嵌入的信息文件当前位的位置 {e,n}是公钥
我的问题是如何找到像素位置?
答案 0 :(得分:1)
找到像素的位置是一个复杂执行的简单概念。我在这里编写了一些代码,采用BufferedImage并在其中搜索特定颜色的像素。
import java.awt.Color;
import java.awt.image.BufferedImage;
import java.io.File;
import javax.imageio.ImageIO;
import java.io.IOException;
public class pixelSearch {
public static void main(String[] args) {
//I don't know where you're getting your image but i'll get one from file
File image = new File("image.bmp");
try {
BufferedImage imageToSearch = ImageIO.read(image);
Color colorToFind = new Color(255,255,255); //define color to search for with RGB vals 255,255,255
//for more information on constructing colors look here: http://docs.oracle.com/javase/7/docs/api/java/awt/Color.html
int[] pixelCoordinates = pSearch( colorToFind, imageToSearch ); //search for the pixel
System.out.println("Found pixel at (" + pixelCoordinates[0] + "," + pixelCoordinates[1] + ")."); //display coordinates
} catch (IOException e) {
System.out.println(e.toString());
}
}
private static int[] pSearch ( Color c, BufferedImage pic ){
int cVal = c.getRGB(); //get integer value of color we are trying to find
int x1 = 0;
int y1 = 0;
int x2 = pic.getWidth();
int y2 = pic.getHeight();
int[] XArray = new int[x2-x1+1]; //create an array to hold all X coordinates in image
int iterator = 0;
while (iterator <= x2) {
XArray[iterator] = x1 + iterator;
iterator++;
}
int [] YArray = new int[y2-y1+1]; //create an array to hold all Y coordinates in image
iterator = 0;
while (iterator <= y2) {
YArray[iterator] = y1 + iterator;
iterator++;
}
//next we iterate throug all the possible coordinates to check each pixel
for (int yVal : YArray) {
for (int xVal : XArray) {
int color = pic.getRGB(xVal, yVal); //get the color of pixel at coords (xVal, yVal)
if (color == cVal) { //if the color is equal to the one we inputted to the function
int[] cPos = {xVal, yVal}; //store the coordinates
return cPos; //return the coordinates
}
}
}
int[] returnVal = {-1,-1}; //if we didn't find it return -1, -1
return returnVal;
}
}