存储过程计算应税金额

时间:2013-03-21 14:12:47

标签: mysql sql database stored-procedures

我一直在计算员工的年度应税金额而不是改变工资率。

salary_assigned_date | salary
-------------------------------
    2011-12-06          5000
    2012-01-05          10000
    2012-02-10          15000
    2012-04-08          20000
    2012-08-01          28000

现在,我按月计算的2012年应税金额应如下:

我假设没有。一个月内的日子为30岁。

month   |   taxable_amount
-----------------------------------------------
  01            833.33 + 8333.33   /* Since salary has been changed 
                                      at 6th of month, 
                                      for 5 days, 
                                      taxable amount = 5000/30*5 
                                      => 833.33 
                                      and for remaining 25 days
                                      = 10000/30*25=> 8333.33
                                      and same case for remaining months.*/
  02            3000 + 10500
  03            15000
  04            4666.67 + 15333.33
  05            20000
  06            20000
  07            20000
  08            933.33 + 27066.67
  09            28000
  10            28000
  11            28000
  12            28000

我尝试编写存储过程以计算应税金额但我无法完成此操作。

有人可以为此提供帮助吗?

1 个答案:

答案 0 :(得分:1)

你需要一个sql语句,它将表中的记录连接到具有下一个工资值的表中的记录...你还需要使用CTE(或者任何** MySQL equivalent *存在)生成没有发生工资变化的所有月份。 * [感谢@ Neville的评论]

请原谅SQL服务器语法,我不会为你查找MySQL等价物......意图应该清楚。我知道MySQL有自己的功能,相当于SQL服务器的日期函数getdate()DateDiff()DateAdd()Day()

 With Dates(dt) As
 ( Select min(salary_assigned_date) 
   From yourTable 
   Union All
   Select DateAdd(month,1, dt)
   from dates
   where dt < getdate())  -- replace getdate() with parameter for max date to calculate

  -- If MySQL has no equivalent to CTE, you need to generate a temp table with 
  -- these dates in it and use that instead of the [Dates] construction

   Select t.dt, t.salary/30.0 * (day(t.dt)-1) +
        + n.salary/30.0 * (31 - day(t.dt))
   From Dates d 
      join yourTable t On t.salary_assigned_date = 
                    (Select Min(salary_assigned_date) 
                     From test where salary_assigned_date >= d.dt)
      join yourTable n On n.salary_assigned_date = 
                    (Select Min(salary_assigned_date) 
                      From test where salary_assigned_date > d.dt)

   Select t.salary/30.0 * (day(t.salary_assigned_date)-1) +
        + n.salary/30.0 * (31 - day(t.salary_assigned_date))
   From table t
       join table n On n.salary_assigned_date =
                    (Select Min(salary_assigned_date) From table
                     Where salary_assigned_date > t.salary_assigned_date)