我一直在计算员工的年度应税金额而不是改变工资率。
salary_assigned_date | salary
-------------------------------
2011-12-06 5000
2012-01-05 10000
2012-02-10 15000
2012-04-08 20000
2012-08-01 28000
现在,我按月计算的2012年应税金额应如下:
我假设没有。一个月内的日子为30岁。
month | taxable_amount
-----------------------------------------------
01 833.33 + 8333.33 /* Since salary has been changed
at 6th of month,
for 5 days,
taxable amount = 5000/30*5
=> 833.33
and for remaining 25 days
= 10000/30*25=> 8333.33
and same case for remaining months.*/
02 3000 + 10500
03 15000
04 4666.67 + 15333.33
05 20000
06 20000
07 20000
08 933.33 + 27066.67
09 28000
10 28000
11 28000
12 28000
我尝试编写存储过程以计算应税金额但我无法完成此操作。
有人可以为此提供帮助吗?
答案 0 :(得分:1)
你需要一个sql语句,它将表中的记录连接到具有下一个工资值的表中的记录...你还需要使用CTE(或者任何** MySQL equivalent *存在)生成没有发生工资变化的所有月份。 * [感谢@ Neville的评论]
请原谅SQL服务器语法,我不会为你查找MySQL等价物......意图应该清楚。我知道MySQL有自己的功能,相当于SQL服务器的日期函数getdate()
,DateDiff()
,DateAdd()
和Day()
。
With Dates(dt) As
( Select min(salary_assigned_date)
From yourTable
Union All
Select DateAdd(month,1, dt)
from dates
where dt < getdate()) -- replace getdate() with parameter for max date to calculate
-- If MySQL has no equivalent to CTE, you need to generate a temp table with
-- these dates in it and use that instead of the [Dates] construction
Select t.dt, t.salary/30.0 * (day(t.dt)-1) +
+ n.salary/30.0 * (31 - day(t.dt))
From Dates d
join yourTable t On t.salary_assigned_date =
(Select Min(salary_assigned_date)
From test where salary_assigned_date >= d.dt)
join yourTable n On n.salary_assigned_date =
(Select Min(salary_assigned_date)
From test where salary_assigned_date > d.dt)
Select t.salary/30.0 * (day(t.salary_assigned_date)-1) +
+ n.salary/30.0 * (31 - day(t.salary_assigned_date))
From table t
join table n On n.salary_assigned_date =
(Select Min(salary_assigned_date) From table
Where salary_assigned_date > t.salary_assigned_date)