我正在使用Google's C++ B-tree,我遇到了一个人可能会回答的问题。
首先,我收到以下错误:
In file included from ref_impl/../include/btree_map.h:31:0,
from ref_impl/core.cpp:48:
ref_impl/../include/btree.h: In instantiation of ‘btree::btree_node<Params>::reference btree::btree_node<Params>::value(int) [with Params = btree::btree_map_params<unsigned int, unsigned int, std::less<unsigned int>, std::allocator<std::pair<const unsigned int, unsigned int> >, 256>; btree::btree_node<Params>::reference = std::pair<const unsigned int, unsigned int>&]’:
ref_impl/../include/btree.h:809:33: required from ‘btree::btree_iterator<Node, Reference, Pointer>::pointer btree::btree_iterator<Node, Reference, Pointer>::operator->() const [with Node = btree::btree_node<btree::btree_map_params<unsigned int, unsigned int, std::less<unsigned int>, std::allocator<std::pair<const unsigned int, unsigned int> >, 256> >; Reference = std::pair<const unsigned int, unsigned int>&; Pointer = std::pair<const unsigned int, unsigned int>*; btree::btree_iterator<Node, Reference, Pointer>::pointer = std::pair<const unsigned int, unsigned int>*]’
ref_impl/core.cpp:539:18: required from here
ref_impl/../include/btree.h:557:57: warning: dereferencing type-punned pointer will break strict-aliasing rules [-Wstrict-aliasing]
btree.h:
pointer operator->() const {
return &node->value(position);
}
这似乎是错误的原因。
我的部分代码如下:
auto range = duplicates.equal_range(query_ids_temp[i]);
for (auto it = range.first; it != range.second; ++it) {
//error
std::vector<unsigned int>::iterator pos = std::find(deleted_queries.begin(), deleted_queries.end(), it->second);
//error
if (pos != deleted_queries.end()) {
duplicates.erase(it);
deleted_queries.erase(pos);
} else {
query_ids.push_back(it->second);
}
}
错误似乎是it-&gt; second
另外我试过了:
for (btree_multimap<unsigned int, unsigned int>::iterator it = range.first; it != range.second; ++it) {
//error
auto temp = it->second;
//error
std::vector<unsigned int>::iterator position = std::find(deleted_queries.begin(), deleted_queries.end(), temp);
if (position != deleted_queries.end()) {
duplicates.erase(temp);
deleted_queries.erase(position);
} else {
query_ids.push_back(it->second);
}
}
请注意,错误似乎是在auto temp = it-&gt; second;
我也尝试过:
auto p = duplicates.find(query_ids_temp[i]);
if(p != duplicates.end()) { // found a name
do {
//error
auto temp = p->second;
//error
auto pos = std::find(deleted_queries.begin(), deleted_queries.end(), temp);
if (pos != deleted_queries.end()) {
duplicates.erase(p->second);
deleted_queries.erase(pos);
} else {
query_ids.push_back(p->second);
}
p++;
} while (p != duplicates.upper_bound(query_ids_temp[i]));
}
else{
cout << "Name not found.\n";
}
问题似乎又一样:auto temp = p-&gt; second;
有什么建议吗?
答案 0 :(得分:1)
谷歌B树的核心警告是突变使迭代器无效。 循环内对duplicates.erase()的调用使“p”无效。
出于这个原因,erase()方法返回一个迭代器,因此您可以编写如下内容:
if (...) {
p = duplicates.erase(...);
...
} else {
...
p++;
}
BTW,请提供有关哪个编译器版本发出警告的详细信息。