我怀疑之前已经问过这个问题,但是我找不到它,所以这里有:
在Python上(使用2.7)我创建了一个namedtuple
,如下所示:
>>> sgn_tuple = namedtuple('sgnt',['signal','type'])
>>> a = sgn_tuple("aaa","bbb")
然后我想查看t
的类型,我的结果很奇怪:
>>> type (a)
<class '__main__.sgnt'>
>>> a is tuple
False
>>> a is namedtuple
False
>>> a is sgnt
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
NameError: name 'sgnt' is not defined
>>> a is sgn_tuple
False
>>>
为什么会这样?我希望a
被识别为元组类型,但事实并非如此。任何提示?
答案 0 :(得分:11)
is
不会检查班级成员资格。 is
检查两个对象是否具有相同的id
>>> isinstance(a, tuple)
True
type(a)
不是tuple
,a
是tuple
的子类。
如果您键入verbose=True
,您可以看到它是如何制作的(文本是动态生成的,用于创建类):
>>> sgn_tuple = namedtuple('sgnt',['signal','type'],verbose=True)
class sgnt(tuple):
'sgnt(signal, type)'
__slots__ = ()
_fields = ('signal', 'type')
def __new__(_cls, signal, type):
'Create new instance of sgnt(signal, type)'
return _tuple.__new__(_cls, (signal, type))
@classmethod
def _make(cls, iterable, new=tuple.__new__, len=len):
'Make a new sgnt object from a sequence or iterable'
result = new(cls, iterable)
if len(result) != 2:
raise TypeError('Expected 2 arguments, got %d' % len(result))
return result
def __repr__(self):
'Return a nicely formatted representation string'
return 'sgnt(signal=%r, type=%r)' % self
def _asdict(self):
'Return a new OrderedDict which maps field names to their values'
return OrderedDict(zip(self._fields, self))
__dict__ = property(_asdict)
def _replace(_self, **kwds):
'Return a new sgnt object replacing specified fields with new values'
result = _self._make(map(kwds.pop, ('signal', 'type'), _self))
if kwds:
raise ValueError('Got unexpected field names: %r' % kwds.keys())
return result
def __getnewargs__(self):
'Return self as a plain tuple. Used by copy and pickle.'
return tuple(self)
signal = _property(_itemgetter(0), doc='Alias for field number 0')
type = _property(_itemgetter(1), doc='Alias for field number 1')
这只是Python的exec
。我希望能够解决问题。